If sin θ θ = xy x y and 0o < 90o, then find 1tanθ 1 t a n θ .

Question 1 Report

If sin $θ$ = $\frac{x}{y}$ and 0o < 90o, then find $\frac{1}{t a n θ}$ .

x

√y²−x²

y

x

√y²+ x²

y²−x²

y²−x²

x

Answer Details

$\frac{1}{t a n θ}$ = $\frac{c o s θ}{s i n θ}$
sin $θ$ = $\frac{x}{y}$
cos $θ$ = $\frac{\sqrt{y^{2} - x^{2}}}{y}$

Read lesson note on Sine, Cosine And Tangent Of An Angle (WAEC)

Sine, Cosine And Tangent Of An Angle

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