If the price of oranges was raised by \( \frac{1}{2} \)k per orange. The number of oranges a customer can buy for ?2.40 will be less by 16. What is the pres...

Assessment: JAMB UTME - Mathematics - 1984 Subject: General Mathematics

Question 1 Report

If the price of oranges was raised by \( \frac{1}{2} \)k per orange. The number of oranges a customer can buy for ?2.40 will be less by 16. What is the present price of an orange?

Answer Details
Let x represent the price of an orange and
y represent the number of oranges that can be bought
xy = 240k, y =  240 x .....(i)
If the price of an oranges is raised by  1 2 k per orange, number that can be bought for ?240 is reduced by 16
Hence, y - 16 =  240 x + 1 2
=  480 2 x + 1
=  480 2 x + 1 .....(ii)
subt. for y in eqn (ii)  240 x  - 16
=  480 2 x + 1
=  240 ? 16 x x
=  480 2 x + 1
= (240 - 16x)(2x + 1)
= 480x
= 480x + 240 - 32x2 - 16
480x = 224 - 32x2
x2 = 7
x =  7
= 2.5
= 2 1 2 k

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