If the price of oranges was raised by \(... | JAMB UTME - Mathematics - 1984

Question 1 Report

If the price of oranges was raised by $ \frac{1}{2} $k per orange. The number of oranges a customer can buy for ?2.40 will be less by 16. What is the present price of an orange?

\frac{1}{2}

\frac{2}{15}

\frac{1}{3}

Answer Details

Let x represent the price of an orange and
y represent the number of oranges that can be bought
xy = 240k, y = $\frac{240}{x}$ .....(i)
If the price of an oranges is raised by $\frac{1}{2}$ k per orange, number that can be bought for ?240 is reduced by 16
Hence, y - 16 = $\frac{240}{x + \frac{1}{2}}$
= $\frac{480}{2 x + 1}$
= $\frac{480}{2 x + 1}$ .....(ii)
subt. for y in eqn (ii) $\frac{240}{x}$ - 16
= $\frac{480}{2 x + 1}$
= $\frac{240 - 16 x}{x}$
= $\frac{480}{2 x + 1}$
= (240 - 16x)(2x + 1)
= 480x
= 480x + 240 - 32x2 - 16
480x = 224 - 32x2
x2 = 7
x = $\sqrt{7}$
= 2.5
= 2 $\frac{1}{2}$ k

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If the price of oranges was raised by \( \frac{1}{2} \)k per orange. The number of oranges a customer can buy for ?2.40 will be less by 16. What is the pres...

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If the price of oranges was raised by \( \frac{1}{2} \)k per orange. The number of oranges a customer can buy for ?2.40 will be less by 16. What is the pres...

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