In the figure, 0 is the centre of circle PQ..

Question 1 Report

In the figure, 0 is the centre of circle PQRS and PS//RT. If PRT = 135, then PSO is

\frac{1}{2}

^{\circ}

\frac{1}{2}

^{\circ}

\frac{1}{2}

^{\circ}

^{\circ}

^{\circ}

Answer Details

< R = 180 $^{\circ}$ - 45 $^{\circ}$ (sum of angles on a straight line)

< R = < P = 45 $^{\circ}$ (corresponding angles)

< PSO = < P = 45 $^{\circ}$ ( $△$ PSO is a right angle)