In the figure, TSP = PRQ, QR = 8cm, PR = 6c..

Question 1 Report

In the figure, TSP = PRQ, QR = 8cm, PR = 6cm and ST = 12cm. Find the length SP.

4cm

16cm

9cm

14cm

Impossible, insufficient data

Answer Details

$\frac{P Q}{6 + R T} = \frac{6}{12} = \frac{6}{P S}$ (Similar triangles)

$\frac{6}{12} = \frac{8}{P S}$

PS = $\frac{12 \times 8}{6}$

= 16cm