Solve for t in the equation 34 3 4 t + 13 1 3 (21 - t) = 11

Solve for t in the equation $\frac{3}{4}$t + $\frac{1}{3}$(21 - t) = 11

Answer Details

$\frac{3}{4}$ t + $\frac{1}{3}$ (21 - t) = 11
Multiply through by the LCM of 4 and 3 which is 12
12 x($\frac{3}{4}$ t) + 12 x ($\frac{1}{3}$ (21 - t)) = (11 x 12)
9t + 4(21 - t) = 132
9t + 84 - 4t = 132
5t + 84 = 132
5t = 132 - 84 = 48
t = $\frac{48}{5}$
t = 9 $\frac{3}{5}$