A trader realises 10x - x2 2 Naira profit from the sale of x bags of corn. How many bags will give him the maximum profit?

A trader realises 10x - x${}^2$ Naira profit from the sale of x bags of corn. How many bags will give him the maximum profit?

Answer Details

Profit (P) = $10x-x^2$
Maximum profit can be achieved when the differential of profit with respect to number of bags(x) is 0
i.e. $\frac{\delta p}{\delta x}$ = 0
$\frac{\delta p}{\delta x}$ = 10 - 2x = 0
10 = 2x
Then x = $\frac{10}{2}$ = 5