Question 1 Report
In the diagram, GI is a tangent to the circle at H. If EF||GI, calculate the size of ∠EHF.
Answer Details
∠FHI = 54° = ∠EFH (alternating angles) ∠FEH = ∠EFH (isosceles triangle) ∠EHF + ∠FEH + ∠EFH = 180° (sum of the angles in a triangle) ∠EHF = 180° - (∠FEH + ∠EFH) ∠EHF = 180° - (54° - 54°) = 180° - 108° ∠EHF = 72°