If P = [Q(R−T)15 Q ( R − T ) 15 ] 13 1 3 ma..

Question 1 Report

If P = [ $\frac{Q (R - T)}{15}$ ] $^{\frac{1}{3}}$ make T the subject of the relation

T =

\frac{R + P^{3}}{15 Q}

T =

\frac{R - 15 P^{3}}{Q}

T =

\frac{R - 15 P^{3}}{Q}

T =

\frac{15 R - Q}{P^{3}}

Answer Details

Taking the cube of both sides of the equation give
P $^{3}$ = $\frac{Q (R - T)}{15}$
Cross multiplying
15P $^{3}$ = Q(R - T)
Divide both sides by Q
$\frac{15 P^{3}}{Q}$ = R - T
Rearranging gives
T = R - $\frac{15 P^{3}}{Q}$
= $\frac{R Q - 15 P^{3}}{Q}$

View Answer

If P = [Q(R−T)15 Q ( R − T ) 15 ] 13 1 3 make T the subject of the relation