If \( P = \left[\frac{Q(R-T)}{15}\right]^{\frac{1}{3}} \) make T the subject of the relation
Answer Details
Taking the cube of both sides of the equation give P3 = Q(R−T)15 Cross multiplying 15P3 = Q(R - T) Divide both sides by Q 15P3Q = R - T Rearranging gives T = R - 15P3Q = RQ−15P3Q