Two sisters, Taiwo and Kehinde, own a store. The ratio of Taiwo's share to Kehinde's is 11:9. Later Kehinde sells \( \frac{2}{3} \) of her share to Taiwo fo...
Question 1 Report
Two sisters, Taiwo and Kehinde, own a store. The ratio of Taiwo's share to Kehinde's is 11:9. Later Kehinde sells \( \frac{2}{3} \) of her share to Taiwo for ₦720.00. Find the value of the store
Answer Details
The problem can be solved using algebra. Let's start by assuming that Taiwo's share is 11x and Kehinde's share is 9x. Then the total value of the store is 20x.
Kehinde sells 2/3 of her share to Taiwo for ₦720.00. This means that Taiwo paid ₦720.00 for 2/3 of 9x, which is (2/3) * 9x = 6x. So we have:
6x = 720
Solving for x, we get:
x = 120
Now we can find the total value of the store:
20x = 20 * 120 = ₦2,400.00
Therefore, the answer is option (B), ₦2,400.00.
In summary, we used algebra to solve the problem by assuming values for Taiwo's and Kehinde's shares and finding the total value of the store. Then we used the information about Kehinde's sale to find the value of x and ultimately the total value of the store.
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