P=[Q(R−T)15]13 P = [ Q ( R − T ) 15 ] 1 3 M..

Question 1 Report

$P = {[\frac{Q (R - T)}{15}]}^{\frac{1}{3}}$

Make T the subject of the relation.

T = \frac{R + P3}{15 Q}

T = \frac{R - 15 P^{3}}{Q}

T = R - \frac{15 P^{3}}{Q}

T = \frac{15 R + Q}{P^{3}}

Answer Details

$P = {[\frac{Q (R - T)}{15}]}^{\frac{1}{3}}$
$P^{3} = \frac{Q (R - T)}{15}$
$15 P^{3} = Q (R - T)$
$\frac{15 P^{3}}{Q} = R - T$
$T = R - \frac{15 P^{3}}{Q}$

Read lesson note on Change Of Subject Of A Formula/Relation (WAEC)

Read lesson note on Solution Of Linear Equations (WAEC)

Change Of Subject Of A Formula/Relation

Solution Of Linear Equations

View Answer

P=[Q(R−T)15]13 P = [ Q ( R − T ) 15 ] 1 3 Make T the subject of the relation.