A body of mass 10kg moving with a velocity of 5\(ms^{-1}\) collides with another body of mass 15kg moving in the same direction as the first with a velocity...
Question 1 Report
A body of mass 10kg moving with a velocity of 5\(ms^{-1}\) collides with another body of mass 15kg moving in the same direction as the first with a velocity of 2\(ms^{-1}\). After collision, the two bodies move together with a common velocity v\(ms^{-1}\).
Answer Details
We can use the law of conservation of momentum to solve this problem. According to the law, the total momentum of the system before the collision is equal to the total momentum after the collision.
Before collision:
- Body 1 mass = 10kg, velocity = 5\(ms^{-1}\), momentum = 50 kg\(ms^{-1}\)
- Body 2 mass = 15kg, velocity = 2\(ms^{-1}\), momentum = 30 kg\(ms^{-1}\)
- Total momentum before collision = 50 + 30 = 80 kg\(ms^{-1}\)
After collision:
- Total mass = 10 + 15 = 25kg
- Let v be the common velocity of the two bodies after the collision
- Total momentum after collision = 25v
Equating the two momenta, we get:
80 = 25v
v = 80/25 = 3.2
Therefore, the common velocity of the two bodies after the collision is 3.2\(ms^{-1}\). Answer: (a) 3.2
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