The table below gives the ages, to the nearest 5 years of 50 people. Age in years 10 15 20 25 30 No of people 8 19 10 7 6 (a) Construct a cumulative frequen...

Assessment: WAEC SSCE - General Mathematics - 1994 (Essay) Subject: General Mathematics

Question 1 Report

The table below gives the ages, to the nearest 5 years of 50 people.

Age in years 10 15 20 25 30
No of people 8 19 10 7 6

(a) Construct a cumulative frequency table for the distribution.

(b) Draw a cumulative frequency curve (Ogive)

(c) From your Ogive, find the : (i) median age ; (ii) number of people who are at most 15 years of age ; (iii) number of people who are between 20 and 25 years of age.

Answer Details

(a) Cumulative frequency table. Ages are given to the nearest 5 years, so the class boundaries are \(7.5\text{-}12.5,\ 12.5\text{-}17.5,\) etc.

Age (nearest 5 yr)Upper boundaryNo. of peopleCumulative freq.
1012.588
1517.51927
2022.51037
2527.5744
3032.5650

(b) Plot cumulative frequency against upper class boundary and join with a smooth curve (ogive).

(c)(i) Median age. At \(\frac{N}{2} = 25\), reading across from the ogive:

\[\text{Median} = 12.5 + \frac{25 - 8}{19}\times 5 \approx 17 \text{ years}\]

(c)(ii) At most 15 years. Reading up from \(x = 15\): about 18 people.

(c)(iii) Between 20 and 25 years. Reading the ogive at 25 and at 20 and subtracting:

\[\approx 40.5 - 32 \approx 8 \text{ people}\]

Download The App On Google Playstore

Everything you need to excel in your exams

Green Bridge CBT Mobile App
Personalized AI Learning Chat Assistant
200,000+ Exam Questions Across IGCSE, JAMB, WAEC & NECO
Over 3,900 Lesson Notes
Offline Support - Learn Anytime, Anywhere
Green Bridge Timetable
Literature Summaries & Potential Questions
Track Your Performance & Progress
In-depth Explanations for Comprehensive Learning