Question 1 Report
A straight line makes an angle of 30° with the positive x-axis and cuts the y-axis at y = 5. Find the equation of the straight line.
Answer Details
Cos 30 = 5/x x cos 30 = 5, => x = 5√3 Coordinates of P = -5, 3, 0 Coordinates of Q = 0, 5 Gradient of PQ = (y2 - y1) (X2 - X1) = (5 - 0)/(0 -5√3) = 5/5√3 = 1/√3 Equation of PQ = y - y1 = m (x -x1) y - 0 = 1/√3 (x -(-5√3)) Thus: √3y = x + 5√3