P(-6, 1) and Q(6, 6) are the two ends of the diameter of a given circle. Calculate the radius.

The diameter of a circle is the distance between any two points on the circle passing through the center of the circle. In this problem, we are given the two endpoints of the diameter of a circle: P(-6, 1) and Q(6, 6). We can find the distance between these two points using the distance formula: d = sqrt((x2 - x1)^2 + (y2 - y1)^2) where d is the distance between the two points (P and Q in this case), and (x1, y1) and (x2, y2) are the coordinates of the two points. So, substituting the given values in the distance formula, we get: d = sqrt((6 - (-6))^2 + (6 - 1)^2) d = sqrt(12^2 + 5^2) d = sqrt(144 + 25) d = sqrt(169) d = 13 Therefore, the diameter of the circle is 13 units. The radius of the circle is half the diameter, so: radius = diameter / 2 = 13 / 2 = 6.5 Hence, the radius of the circle is 6.5 units. So, the answer is.