Take \(\mathcal{E}\) to be every whole number strictly between 10 and 30. \(C = \{x : x \text{ is a multiple of 9}\}\) and \(D = \{x : x \text{ is an even n...

Assessment: Mathematics Specification A 4MA1 | Paper 2 Mock 01 | Written Paper 2 (2F/2H) Subject: Mathematics Specification A - 4MA1

Question 1 Report

Take \(\mathcal{E}\) to be every whole number strictly between 10 and 30.

\(C = \{x : x \text{ is a multiple of 9}\}\) and \(D = \{x : x \text{ is an even number}\}\). The number line below shows the elements of \(D\) within \(\mathcal{E}\).

1112141618202224262829D© EAGLE BEACON GLOBAL
  1. List the elements of \(C\). (2)
  2. List the elements of \(C \cup D\). (2)
  3. Write down \(n(D')\). (1)

Answer Details

This question lists a set defined by a divisibility rule, reads a second set from a number line, then finds their union and a complement.

(a) The universal set is every whole number strictly between 10 and 30 (11 to 29 inclusive). Listing the multiples of 9 in this range: \[ C = \{18, 27\} \] [2 marks]

(b) Reading the even numbers marked on the number line: \(D = \{12, 14, 16, 18, 20, 22, 24, 26, 28\}\). Combining \(C\) and \(D\) without repeating the shared value 18: \[ C \cup D = \{12, 14, 16, 18, 20, 22, 24, 26, 27, 28\} \] [2 marks]

(c) There are 19 numbers in the universal set (11 to 29 inclusive), and \(n(D) = 9\), so: \[ n(D') = 19 - 9 = 10 \] [1 mark]

Since 18 is both a multiple of 9 and even, it appears in both \(C\) and \(D\); when forming the union, it is written into the combined list only once, not twice.

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