Find the sum of the first 18 terms of the progression 3, 6, 12......

Assessment: JAMB UTME - Mathematics - 1990 Subject: General Mathematics

Question 1 Report

Find the sum of the first 18 terms of the progression 3, 6, 12......
Answer Details
3 + 6 + 12 + .....18thy term
1st term = 3, common ratio  6 3  = 2
n = 18, sum og GP is given by Sn = a ( r n − 1 ) r − 1
s18 = 3 ( 2 18 − 1 ) 2 − 1
= 3(217 - 1)

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