Find the sum of the first 18 terms of the progression 3, 6, 12......

Question 1 Report

3(217 - 1)

3(218 - 1)

3(218 + 1)

3(217 - 1)

Answer Details

3 + 6 + 12 + .....18thy term
1st term = 3, common ratio $\frac{6}{3}$ = 2
n = 18, sum og GP is given by Sn = a $\frac{(r^{n} - 1)}{r - 1}$
s18 = 3 $\frac{(2^{18} - 1)}{2 - 1}$
= 3(217 - 1)

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Sequence And Series

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