Question 1 Report
Find the sum of the first 18 terms of the progression 3, 6, 12......
Answer Details
3 + 6 + 12 + .....18thy term 1st term = 3, common ratio 63 6 3 = 2 n = 18, sum og GP is given by Sn = a(rn−1)r−1 ( r n − 1 ) r − 1 s18 = 3(218−1)2−1 ( 2 18 − 1 ) 2 − 1 = 3(217 - 1)