Simplify √160r2 160 r 2 + √71r4 71 r 4 + √1..

Question 1 Report

Simplify $\sqrt{160 r^{2}}$ + $\sqrt{71 r^{4}}$ + $\sqrt{100 r^{2}}$

9r2

\sqrt{3 r}

13r

\sqrt{13 r}

Answer Details

$\sqrt{160 r^{2} + 71 r^{4} + 100 r^{8}}$
Simplifying from the innermost radical and progressing outwards we have the given expression
$\sqrt{160 r^{2} + 71 r^{4} + 100 r^{8}}$ = $\sqrt{160 r^{2} + 81 r^{4}}$
$\sqrt{160 r^{2} + 9 r^{2}}$ = $\sqrt{169 r^{2}}$
= 13r

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Surds (radicals)

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Simplify √160r2 160 r 2 + √71r4 71 r 4 + √100r2