Use the information below to answer questions (a)(i) and (a)(ii). Hb Are presents normal haemoglobin, HbS represents sickled haemoglobin. a. A female hetero...
Use the information below to answer questions (a)(i) and (a)(ii). Hb Are presents normal haemoglobin, HbS represents sickled haemoglobin.
a. A female heterozygote for sickle cell married a sickler. With the aid of a genetic diagram, determine the: (i) possible genotypes of their offspring; [8 marks] (ii) phenotypic ratio of the offspring. [2 marks]
b. Explain briefly the reason why a Rhesus negative woman married to a Rhesus positive man might lose her second pregnancy. [5 marks]
c. Name two examples of features in animals that support the theory of use and disuse of body parts as used by Lamarck. [2 marks]
d. List three structures in mammals that are vestigial. [3 marks]
(a)(i) Genetic cross
Let HbA represent the allele for normal haemoglobin and HbS represent the allele for sickle-cell haemoglobin.
Female heterozygote: HbAHbS Male sickler: HbSHbS
The female produces gametes HbA and HbS, while the male produces only HbS gametes.
Punnett square showing the cross between a heterozygous female and a sickler male.
Therefore, the possible genotypes of the offspring are:
HbAHbS, heterozygous normal carrier or sickle-cell trait, 2 out of 4;
HbSHbS, sickler, 2 out of 4.
Genotypic ratio: HbAHbS : HbSHbS = 2:2 = 1:1.
(a)(ii) Phenotypic ratio
Normal carriers (non-sicklers) : sicklers = 1:1.
(b) Rhesus incompatibility and loss of the second pregnancy
A Rhesus-negative woman has no Rh antigen on her red blood cells. If her first foetus is Rhesus-positive, some foetal red blood cells may enter her circulation, especially at delivery when the placenta separates. The Rh antigen stimulates the mother to form anti-Rhesus antibodies. In a later pregnancy with a Rhesus-positive foetus, these antibodies cross the placenta and destroy the foetal red blood cells. The resulting severe haemolysis, called erythroblastosis foetalis, may cause death of the foetus and miscarriage.
(c) Features explained by Lamarck's use and disuse theory
The long neck of the giraffe, attributed to continual stretching to reach high leaves.
The webbed feet of ducks or geese, attributed to constant use in swimming.
Let HbA represent the allele for normal haemoglobin and HbS represent the allele for sickle-cell haemoglobin.
Female heterozygote: HbAHbS Male sickler: HbSHbS
The female produces gametes HbA and HbS, while the male produces only HbS gametes.
Punnett square showing the cross between a heterozygous female and a sickler male.
Therefore, the possible genotypes of the offspring are:
HbAHbS, heterozygous normal carrier or sickle-cell trait, 2 out of 4;
HbSHbS, sickler, 2 out of 4.
Genotypic ratio: HbAHbS : HbSHbS = 2:2 = 1:1.
(a)(ii) Phenotypic ratio
Normal carriers (non-sicklers) : sicklers = 1:1.
(b) Rhesus incompatibility and loss of the second pregnancy
A Rhesus-negative woman has no Rh antigen on her red blood cells. If her first foetus is Rhesus-positive, some foetal red blood cells may enter her circulation, especially at delivery when the placenta separates. The Rh antigen stimulates the mother to form anti-Rhesus antibodies. In a later pregnancy with a Rhesus-positive foetus, these antibodies cross the placenta and destroy the foetal red blood cells. The resulting severe haemolysis, called erythroblastosis foetalis, may cause death of the foetus and miscarriage.
(c) Features explained by Lamarck's use and disuse theory
The long neck of the giraffe, attributed to continual stretching to reach high leaves.
The webbed feet of ducks or geese, attributed to constant use in swimming.