A pendulum bob executing simple harmonic motion has 2cm and 12Hz as amplitude and frequency respectively. Calculate the period of the motion.

Answer Details

The period of a pendulum is the time taken for one complete oscillation or swing. The relationship between the period, T, and frequency, f, of an object in simple harmonic motion is given by: T = 1/f In the question, the frequency of the pendulum is given as 12 Hz. Therefore, we can calculate the period as: T = 1/f = 1/12 Hz = 0.0833 s Rounding off to two significant figures, the period is 0.08s. Therefore, the correct option is (c) 0.08s.