A stone of mass 0.7kg is projected vertically , upwards with a speed of 5ms-1. Calculate the maximum height reached. (Take g as 10ms-2 and neglect air resis...

A stone of mass 0.7kg is projected vertically , upwards with a speed of 5ms^-1. Calculate the maximum height reached. (Take g as 10ms^-2 and neglect air resistance)

Answer Details

The problem involves a projectile motion where a stone is projected vertically upwards with a speed of 5 m/s. We are given the mass of the stone as 0.7 kg, the initial velocity as 5 m/s, the acceleration due to gravity as 10 m/s\(^2\), and we need to find the maximum height reached by the stone. In projectile motion, the vertical motion of the stone can be analyzed independently of the horizontal motion. The initial vertical velocity of the stone is 5 m/s, and the acceleration due to gravity is 10 m/s\(^2\), acting in the opposite direction to the motion of the stone. Using the kinematic equation of motion for vertical motion, we can calculate the maximum height reached by the stone. The equation is: v\(^2\) = u\(^2\) + 2as where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity, and s is the displacement. At the maximum height, the final velocity of the stone is zero, and the displacement is the maximum height reached, h. Substituting the given values, we get: 0\(^2\) = 5\(^2\) - 2 × 10 × h Simplifying this equation, we get: h = 1.25 m Therefore, the maximum height reached by the stone is 1.25 m.