A piece of substance of specific heat capacity 450Jkg?1 ? 1 k1 1 falls through a vertical distance of 20m from rest. Calculate the rise in temperature of th...

Answer Details

Using the law of conservation of energy

mc?? $??$ = mgh

?? $??$ = ghc=10×20450=49 $\frac{gh}{c}=\frac{10\times 20}{450}=\frac{4}{9}$ºC