0.5kg of water at 10ºC is completely converted to ice at 0ºC by extracting (88000) of heat from it. If the specific heat capacity of water is 4200jkg\(^{1}\...

Assessment: JAMB UTME - Physics - 2021 Subject: Physics

Question 1 Report

0.5kg of water at 10ºC is completely converted to ice at 0ºC by extracting (88000) of heat from it. If the specific heat capacity of water is 4200jkg$^{1}$ Cº. Calculate the specific latent heat of fusion of ice.

9.0kjkg

^{- 1}

84.0kjkg

^{- 1}

134.0kjkg

^{- 1}

168.0kjkg

^{- 1}

Answer Details

Heat involved (H) = 88,000J, Mass(M)= 0.5kg, specific heat capacity of water(C) = 4200JkgºC,

Specific latent heat of fusion(L) = ?, Temperature change(Δθ) = θ2 - θ1 = (10 - 0)° = 10°

H = MCΔθ + ML

H = M(CΔθ + L) --> $\frac{H}{M}$ = CΔθ + L

: L = $\frac{H}{M}$ - CΔθ = $\frac{88, 000}{0.5}$ - 4200 $\times$ 10

L = 176,000 - 42000 = 134,000

L = 134,000 or 134kj/kg

Read lesson note on Temperature And Its Measurement (JAMB)

Temperature And Its Measurement

View Answer

0.5kg of water at 10ºC is completely converted to ice at 0ºC by extracting (88000) of heat from it. If the specific heat capacity of water is 4200jkg\(^{1}\...

Related Questions

Download The App On Google Playstore