If the frequency of an emitted x-ray is 1.6 x 1016 16 Hz, the accelerating potential is? [e = 1.6 x 10−19 − 19 J, h = 6.63 x 10-34 34 Js]

Answer Details

Given f = 1.6 x1016 ${}^{16}$H3 ${}_3$, h = 6.63 x 10−39 ${}^{-39}$Js

e = 1.6 x 10−19 ${}^{-19}$C, V = ?

V = we=hfe $\frac{w}{e}=\frac{hf}{e}$ = 1.6×1016×6.63×10341.6×10−19 $\frac{1.6\times {10}^{16}\times 6.63\times {10}^{34}}{1.6\times {10}^{-19}}$

= 66.3V