If the frequency of an emitted x-ray is \(1.6 \times 10^{16}\) Hz, the accelerating potential is? [e = \(1.6 \times 10^{-19}\) J, h = \(6.63 \times 10^{-34}...

Given f = 1.6 x1016 ${}^{16}$H3 ${}_3$, h = 6.63 x 10−39 ${}^{-39}$Js

e = 1.6 x 10−19 ${}^{-19}$C, V = ?

V = we=hfe $\frac{w}{e}=\frac{hf}{e}$ = 1.6×1016×6.63×10341.6×10−19 $\frac{1.6\times {10}^{16}\times 6.63\times {10}^{34}}{1.6\times {10}^{-19}}$

= 66.3V