3H2(g) 2 ( g ) + N2 ⇔ 2NH3(g) 3 ( g ) ; H= -ve In the reaction above, lowering of temperature will

Question 1 Report

3H $_{2 (g)}$ + N2 ⇔ 2NH $_{3 (g)}$ ; H= -ve

In the reaction above, lowering of temperature will

have no effect on the equilibrium position

increase the rate of both the forward and reverse reactions equally

favour the forward reactio

favour the reverse reaction

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