The temperature gradient across a copper rod of thickness 0.02m, maintained at two temperature junctions of 20°C and 80°C respectively is

The temperature gradient across a copper rod of thickness 0.02m, maintained at two temperature junctions of 20°C and 80°C respectively is

Answer Details

Temperature Gradient = $\frac{\Delta \text{temp.}}{\text{thickness}}$

= $\frac{80-20}{0.02}$

= $\frac{60}{0.02}$

= 3000Km-1

= 3.0 x 103Km-1