In the series a.c circuit shown above, the p.d across the inductor is 8Vr.m.s and that across the resistor is 6Vr.m.s. The effective voltage is

In the series a.c circuit shown above, the p.d across the inductor is 8Vr.m.s and that across the resistor is 6Vr.m.s. The effective voltage is

Answer Details

To find the effective voltage in an AC circuit with both inductor and resistor, we need to use the concept of phasor diagram. The effective voltage is the hypotenuse of the right-angled triangle formed by the phasor diagram, where the vertical side represents the voltage across the inductor, and the horizontal side represents the voltage across the resistor. Using the given values, we can draw the phasor diagram and calculate the effective voltage as follows: - Let the voltage across the inductor be represented by a vertical phasor of 8V. - Let the voltage across the resistor be represented by a horizontal phasor of 6V. - The hypotenuse of the right-angled triangle formed by the two phasors represents the effective voltage. - Using the Pythagorean theorem, we can find the length of the hypotenuse: - hypotenuse = sqrt(vertical side^2 + horizontal side^2) - hypotenuse = sqrt(8^2 + 6^2) = sqrt(100) = 10V Therefore, the effective voltage in the circuit is 10V. So, the correct option is: - 10V