The solution of the quadratic inequality \( (x^2 + x - 12) \ge 0 \) is
Question 1 Report
The solution of the quadratic inequality \( (x^2 + x - 12) \ge 0 \) is
Answer Details
(x2 + x - 12) 0 , (x - 3)(x + 4) 0
For the condition to hold, each of (x - 3) and (x + 4) must be of the same sign
.i.e. x - 3 0 and x + 4 0
or x - 3 0 and x + 4 0
when x 3, the condition is satisfied
when x -4, the condition is not satisfied.
when x 3, the condition is not satisfied
when x -4 , the condition is not satisfied. Thus, the solution of the inequality is x 3 or x -4 ,
For the condition to hold, each of (x - 3) and (x + 4) must be of the same sign
.i.e. x - 3 0 and x + 4 0
or x - 3 0 and x + 4 0
when x 3, the condition is satisfied
when x -4, the condition is not satisfied.
when x 3, the condition is not satisfied
when x -4 , the condition is not satisfied. Thus, the solution of the inequality is x 3 or x -4 ,
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