Question 1 Report
Determine the value of ∫π20 ∫ 0 π 2 (-2 cosx)dx
Answer Details
Determine the value of ∫π20 ∫ 0 π 2 (-2 cosx)dx ∫π20 ∫ 0 π 2 (-2 cosx)dx = -2 sin x∫π20 ∫ 0 π 2 = 2(sin 0 - sinπ2 π 2 ) = 2(0 - 1) = -2
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