Question 1 Report
If the lines 2y - kx + 2 = 0 and y + x - k2 k 2 = 0 intersect at (1, 2), find the value of k
Answer Details
2y - kx + 2 = 0, @ x = 1, y = -2 2(-2) - k(1) + 2 = 0 -4 - k + 2 = 0 k = -2 Or y + x - k2 k 2 = 0, @ x= 1, y = -2 -2 + 1 - k2 k 2 = 0 -1 = k2 k 2 k = -1 x 2 = -2
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