(a) In < PQS, |PQ| = 12 cm, |PS| = 5 cm, < SPQ = < PRQ = 90°, Find, correct to three significant figures, |PR|. (b) The length of two ladders, L and M are 1...

Assessment: WAEC SSCE - General Mathematics - 2018 (Essay) Subject: General Mathematics

Question 1 Report

(a)       In < PQS, |PQ| = 12 cm, |PS| = 5 cm, < SPQ = < PRQ = 90°, Find, correct to three significant figures, |PR|.

(b) The length of two ladders, L and M are 10m and 12m respectively. They are placed against a wall such that each ladder makes angle with the horizontal ground. If the foot of L is 8m from the foot of the wall.

(i) Draw a diagram to illustrate this information;  (ii) Calculate the height at which M touches the wall.

Answer Details

(a)

In right-angled triangle \(SPQ\),

\[SQ^2=PS^2+PQ^2=5^2+12^2=169.\]

Hence, \(SQ=13\text{ cm}\).

\(PR\) is the perpendicular height from \(P\) to the hypotenuse \(SQ\). Equating the two expressions for the area of \(\triangle SPQ\):

\[\frac12(5)(12)=\frac12(13)(PR).\]

\[PR=\frac{5\times12}{13}=4.615\ldots\text{ cm}.\]

\[\boxed{PR=4.62\text{ cm}}\qquad\text{(correct to 3 significant figures).}\]


(b)(i) The required diagram is:

figure
Diagram showing ladders \(L\) and \(M\) against a vertical wall, each making the same angle \(\theta\) with the horizontal ground.

(b)(ii)

For ladder \(L\), let \(\theta\) be its angle with the horizontal ground. Then

\[\cos\theta=\frac{8}{10}=0.8.\]

Therefore,

\[\sin\theta=\sqrt{1-0.8^2}=\sqrt{0.36}=0.6.\]

Since ladder \(M\) makes the same angle \(\theta\) with the ground, if \(h\) is the height at which it touches the wall,

\[\sin\theta=\frac{h}{12}.\]

\[h=12(0.6)=7.2\text{ m}.\]

\[\boxed{\text{Ladder }M\text{ touches the wall }7.2\text{ m above the ground.}}\]

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