Question 1 Report
In the diagram. PQR is an isosceles triangle. If the perimeter of the triangle is 28 cm, find the:
a. values of x and y;
b. lengths of the sides of the triangle.
In triangle PQR the three sides are marked as follows: \(|PQ| = 2y + x\), \(|QR| = 4y\) and \(|PR| = 6y - 2x + 1\). Since PQR is isosceles the two slant sides are equal, \(|QR| = |PR|\).
(a) Values of x and y
Perimeter equation:
\[ (2y + x) + 4y + (6y - 2x + 1) = 28 \]
\[ 12y - x + 1 = 28 \quad\Rightarrow\quad 12y - x = 27 \quad\text{...(1)} \]
Isosceles equation \((|QR| = |PR|)\):
\[ 4y = 6y - 2x + 1 \quad\Rightarrow\quad 2x - 2y = 1 \quad\text{...(2)} \]
From (1), \(x = 12y - 27\). Substituting into (2):
\[ 2(12y - 27) - 2y = 1 \Rightarrow 24y - 54 - 2y = 1 \Rightarrow 22y = 55 \]
\[ y = \frac{55}{22} = \frac{5}{2} = 2\tfrac{1}{2} \]
\[ x = 12\left(\tfrac{5}{2}\right) - 27 = 30 - 27 = 3 \]
Hence x = 3 and y = 2\(\tfrac{1}{2}\) (i.e. 2.5).
(b) Lengths of the sides
Check: \(8 + 10 + 10 = 28\) cm, which agrees with the given perimeter, and \(|QR| = |PR| = 10\) cm confirms the triangle is isosceles.
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