Marks 10 - 19 20 - 29 30 - 39 40 - 49 50 - 59 60 - 69 70 - 79 80 - 89 90 - 99 Frequency 2 2 2 8 13 11 12 10 4 The table shows the distribution of marks scor...

Assessment: WAEC SSCE - Further Mathematics - 2020 (Essay) Subject: Further Mathematics

Question 1 Report

Marks 10 - 19 20 - 29 30 - 39 40 - 49 50 - 59 60 - 69 70 - 79 80 - 89 90 - 99
Frequency 2 2 2 8 13 11 12 10 4

The table shows the distribution of marks scored by 64 students in a test

(a) Draw a histogram for the distribution.

(b) Use the histogram to estimate the modal score.

Answer Details

The class widths are all equal to 10, so the heights of the histogram bars are the frequencies.

MarksClass boundariesFrequency
10–199.5–19.52
20–2919.5–29.52
30–3929.5–39.52
40–4939.5–49.58
50–5949.5–59.513
60–6959.5–69.511
70–7969.5–79.512
80–8979.5–89.510
90–9989.5–99.54

(a) Histogram:

graph
Histogram with contiguous bars over the class boundaries 9.5–19.5, 19.5–29.5, …, 89.5–99.5. The respective bar heights are 2, 2, 2, 8, 13, 11, 12, 10 and 4.

(b) The modal class is 50–59, since it has the greatest frequency, 13.

Using the intersecting diagonals from the top corners of the modal rectangle to the top corners of the adjacent rectangles gives

\[\text{Mode}=L+\frac{f_m-f_1}{(f_m-f_1)+(f_m-f_2)}\times c\]

where \(L=49.5\), \(f_m=13\), \(f_1=8\), \(f_2=11\), and \(c=10\).

\[\text{Mode}=49.5+\frac{13-8}{(13-8)+(13-11)}\times10\]

\[=49.5+\frac{5}{7}\times10=56.64\]

Hence, the estimated modal score is \(\boxed{57\text{ marks}}\).

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