The correct arrangement of gases in the order of increasing rate of diffusion is [H = 1, C = 12, N = 14, O = 16, S = 32]

Assessment: JAMB UTME - Chemistry - 2025 Subject: Chemistry

Question 1 Report

The correct arrangement of gases in the order of increasing rate of diffusion is

[H = 1, C = 12, N = 14, O = 16, S = 32]

Answer Details

According to Graham's law of diffusion, the rate of diffusion of a gas is inversely proportional to the square root of its molar mass:

\[\text{Rate} \propto \frac{1}{\sqrt{M}}\]

This means lighter gases diffuse faster and heavier gases diffuse slower. To arrange gases in order of increasing rate of diffusion, we arrange them from heaviest (slowest) to lightest (fastest).

Calculate the molar masses of the gases that appear in the options:

GasMolar Mass (g/mol)
SO232 + 2(16) = 64
O22(16) = 32
NH314 + 3(1) = 17
H22(1) = 2

Arranging from heaviest to lightest (i.e., increasing rate of diffusion):

SO2 (64) → O2 (32) → NH3 (17) → H2 (2)

This matches the sequence SO2, O2, NH3, H2. The heaviest gas (SO2) diffuses most slowly, and the lightest gas (H2) diffuses most rapidly.

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