If 5g of Iron filling was reacted with excess dilute H\(_2\)SO\(_4\) to evolve hydrogen gas, which came to completion after 10 min, calculate the rate of re...
Question 1 Report
If 5g of Iron filling was reacted with excess dilute H\(_2\)SO\(_4\) to evolve hydrogen gas, which came to completion after 10 min, calculate the rate of reaction in g/hr.
Answer Details
The rate of reaction measures how quickly a reactant is consumed or a product is formed over a given period. Here, 5 g of iron filings reacted completely with excess dilute \(\text{H}_2\text{SO}_4\) in 10 minutes.
The rate of reaction (in terms of mass of reactant consumed per unit time) is:
\[\text{Rate} = \frac{\text{mass of reactant consumed}}{\text{time taken}}\]Substituting the given values:
\[\text{Rate} = \frac{5\text{ g}}{10\text{ min}} = 0.5\text{ g/min}\]The question asks for the rate in grams per hour. Since there are 60 minutes in one hour:
\[\text{Rate} = 0.5\text{ g/min} \times 60\text{ min/hr} = 30\text{ g/hr}\]The rate of reaction is 30 g/hr.
A common mistake is to forget the unit conversion from minutes to hours, which would give an incorrect answer of 0.5 g/min. Always check that the units in your final answer match what the question requests.
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