Question 1 Report
C\(_2\)H\(_5\)OH + CH\(_3\)COOH ⇌ CH\(_3\)COOC\(_2\)H\(_5\) + H\(_2\)O
The reaction above is
The equation shows ethanol (C2H5OH) reacting with ethanoic acid (CH3COOH) to form ethyl ethanoate (CH3COOC2H5) and water (H2O).
This is an esterification reaction. Esterification is the reaction between a carboxylic acid and an alcohol to produce an ester and water. It is typically catalysed by a concentrated strong acid such as tetraoxosulphate(VI) acid (H2SO4), and the reaction is reversible, indicated by the equilibrium sign (⇌).
The general equation is:
\[\text{Carboxylic acid} + \text{Alcohol} \xrightleftharpoons{\text{H}_2\text{SO}_4} \text{Ester} + \text{Water}\]
The other options do not apply here:
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