Question 1 Report
The table compares the properties of two compounds. Compound J is an ionic compound and compound L is a simple molecular compound.
| Property | Compound J | Compound L |
|---|---|---|
| Melting point / °C | 850 | −85 |
| Conducts electricity as a solid | no | no |
| Conducts electricity when molten | yes | no |
| Solubility in water | soluble | insoluble |
(a) State the type of structure present in compound J. [1]
(b) Name the type of bond found within a molecule of compound L. [1]
(c) Explain, in terms of structure and bonding, why compound J has a much higher melting point than compound L. [3]
(d) Explain, in terms of particles, why solid compound J does not conduct electricity but molten compound J does. [3]
(e) Explain why compound J is a solid at room temperature but compound L is a gas. [2]
(f) Compound J dissolves in water to form a solution that conducts electricity. Explain why the solution conducts. [2]
(g) Suggest why compound L does not conduct electricity in any state. [1]
(h) State the name given to the charged particles present in compound J. [2]
This question contrasts a giant ionic compound (J) with a simple molecular compound (L), using structure and bonding to explain every property.
(a) Compound J has a giant ionic lattice (giant ionic structure) [1]. [1]
(b) Within a molecule of the simple molecular compound L, the atoms are joined by covalent bonds (shared pairs of electrons) [1]. [1]
(c) J is a giant ionic lattice with strong electrostatic forces of attraction between oppositely charged ions, so a lot of energy is needed to break them [1][1]; L is simple molecular, with only weak intermolecular forces between separate molecules that need little energy to overcome [1]. This is why J melts at 850 °C but L at \(-85\) °C. [3]
(d) In solid J the ions are held in fixed positions in the lattice and cannot move [1]; when J is molten the lattice breaks down and the ions become free to move [1]; the moving ions then carry the electric charge, so molten J conducts [1]. [3]
(e) The strong forces between the ions in J hold the particles firmly together, so it is a solid at room temperature [1]; the weak forces between L's molecules are so easily overcome that L is a gas at room temperature [1]. [2]
(f) When J dissolves, the lattice breaks up and the ions separate and become free to move [1]; these mobile ions carry the charge through the solution, so it conducts [1]. [2]
(g) L contains no ions and no other free-moving charged particles (its electrons are held in fixed covalent bonds), so it cannot conduct in any state [1]. [1]
(h) The charged particles in J are ions [1] - specifically positive cations and negative anions [1]. [2]
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