Question 1 Report
\(ABCD\) is a rectangle with \(AB = 12\) cm and \(BC = 9\) cm.
(a) Write down the mathematical name of angle \(ABC\). [1]
(b) Work out the perimeter of \(ABCD\). [2]
(c) Work out the length of the diagonal \(AC\). [2]
(d) Write down the order of rotational symmetry of \(ABCD\). [1]
(a) Angle \( ABC \) is a corner of the rectangle, and every corner of a rectangle is exactly \( 90^\circ \), which is called a right angle. [B1]
(b) Opposite sides of a rectangle are equal, so \( AB = DC = 12 \) cm and \( BC = AD = 9 \) cm:
\[ 2 \times (12 + 9) \] [M1] \[ = 2 \times 21 = 42 \text{ cm} \] [A1](c) The diagonal \( AC \) is the hypotenuse of the right-angled triangle \( ABC \), whose shorter sides are \( AB = 12 \) cm and \( BC = 9 \) cm. By Pythagoras' theorem:
\[ AC = \sqrt{12^2 + 9^2} \] [M1] \[ = \sqrt{144 + 81} = \sqrt{225} = 15 \text{ cm} \] [A1](d) Turning the rectangle through \( 180^\circ \) about its centre maps it exactly onto itself, and a further \( 180^\circ \) returns it to the start, so it fits onto itself twice in a full turn. The order of rotational symmetry is \( 2 \). [B1]
The right angle at \( B \) is what makes Pythagoras' theorem available in part (c), and \( 9 \), \( 12 \), \( 15 \) is the \( 3 \), \( 4 \), \( 5 \) triple multiplied by \( 3 \). Note that a rectangle has only \( 2 \) lines of symmetry and rotational symmetry of order \( 2 \), whereas a square has \( 4 \) of each; the diagonals of a rectangle are not lines of symmetry.
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