The plan of a classroom is drawn to a scale of \(1:50\). On the plan the classroom is a rectangle measuring \(16\) cm by \(12\) cm.
(a) Calculate the actual length and the actual width of the classroom, in metres. [2]
(b) Calculate the actual area of the floor, in square metres. [1]
(c) Floor tiles cost \(\$23.50\) for each square metre. Calculate the cost of tiling the floor. [1]
The scale \(1:50\) is unit free, so a plan length in centimetres multiplied by \(50\) gives the real length in centimetres. The later parts then use the real lengths to find an area and a cost.
(a) Length:
\[ 16 \times 50 = 800 \text{ cm} \]
[M1]
\[ 800 \div 100 = 8 \text{ m} \]
Width:
\[ 12 \times 50 = 600 \text{ cm} = 6 \text{ m} \]
So the classroom is \(8\) m by \(6\) m. [A1]
(b) The floor is a rectangle:
\[ 8 \times 6 = 48 \text{ m}^2 \]
[B1]
(c) Each square metre costs \( \$23.50 \), so the total cost is
\[ 48 \times 23.50 = \$1128 \]
[B1]
Two checks are useful. The area could also be found from the plan area \(16 \times 12 = 192\) cm\(^2\) multiplied by \(50^{2}\), giving \(480\,000\) cm\(^2\), which is \(48\) m\(^2\) since \(1\) m\(^2 = 10\,000\) cm\(^2\). And a cost in dollars should be written with the dollar sign and, if it had not come out exact, to two decimal places.