Question 1 Report
The cross-section of a solid prism is a right-angled triangle with sides 3 cm, 4 cm and 5 cm. The prism is 10 cm long.
Calculate the total surface area of the prism.
The total surface area of a prism is the two triangular end faces plus the rectangular side faces, whose combined area equals the triangle's perimeter multiplied by the prism's length.
Area of one triangle \(=\frac{1}{2}\times3\times4=6\) cm\(^2\) [M1].
Perimeter of triangle \(=3+4+5=12\) cm [M1].
Total surface area \(=2\times6+12\times10\) [M1]
\(=132\) cm\(^2\) [A1].
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