Simplify \(2x^{3}y \times 4x^{2}y^{5}\).
Question 1 Report
Simplify \(2x^{3}y \times 4x^{2}y^{5}\).
Answer Details
When multiplying algebraic terms, multiply the numbers together and add the powers of matching letters: \(2 \times 4 = 8\), \(x^{3} \times x^{2} = x^{5}\), and \(y \times y^{5} = y^{6}\), so \(2x^{3}y \times 4x^{2}y^{5} = 8x^{5}y^{6}\) [B2] (1 mark is awarded for getting two of the three parts, the coefficient 8, the power \(x^{5}\), and the power \(y^{6}\), correct).
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