A shopkeeper buys 40 kg of fruits for N120.00. He sells 20 kg at N5.00 per kg, 10 kg at N3.00 per kg, 5 kg at N2.00 per kg and the remaining 5 kg at 50k per...

Assessment: WAEC SSCE - General Mathematics - 1996 (Essay) Subject: General Mathematics

Question 1 Report

A shopkeeper buys 40 kg of fruits for N120.00. He sells 20 kg at N5.00 per kg, 10 kg at N3.00 per kg, 5 kg at N2.00 per kg and the remaining 5 kg at 50k per kg. Calculate the :

(a) amount he realises from the sales ;

(b) total profit / loss ;

(c) percentage profit/ loss on his outlay of N120.00.

Answer Details

Cost price (outlay) \(= \text{N}120.00\) for 40 kg. Note \(50\text{k} = \text{N}0.50\).

(a) Amount realised from sales:

QuantityPrice per kgAmount
20 kgN5.00N100.00
10 kgN3.00N30.00
5 kgN2.00N10.00
5 kgN0.50N2.50
\[ \text{Total sales} = 100 + 30 + 10 + 2.50 = \text{N}142.50. \]

(b) Total profit:

\[ \text{Profit} = 142.50 - 120.00 = \text{N}22.50. \]

Since this is positive, it is a profit.

(c) Percentage profit on outlay of N120.00:

\[ \frac{22.50}{120} \times 100\% = 18.75\%. \]

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