(a) Copy and complete the table for \(y = 3x^{2} - 5x - 7\) x -3 -2 -1 0 1 2 3 4 \(y = 3x^{2} - 5x - 7\) 35 -7 -9 5 (b) Using a scale of 2cm = 1 unit along ...

Assessment: WAEC SSCE - General Mathematics - 1996 (Essay) Subject: General Mathematics

Question 1 Report

(a) Copy and complete the table for \(y = 3x^{2} - 5x - 7\)

x -3 -2 -1 0 1 2 3 4
\(y = 3x^{2} - 5x - 7\) 35 -7 -9 5

(b) Using a scale of 2cm = 1 unit along the x- axis and 2cm = 5 units along the y- axis, draw the graph of \(y = 3x^{2} - 5x - 7\).

(c) On the same axis, draw the graph of \(y + 3x + 2 = 0\).

(d) From your graph, find the : (i) range of values of x for which \(3x^{2} - 5x - 7 < 0\) ; (ii) roots of the equation \(3x^{2} - 2x - 5 = 0\).

Answer Details

(a) For \(y=3x^{2}-5x-7\), the completed table is:

\(x\) \(-3\) \(-2\) \(-1\) \(0\) \(1\) \(2\) \(3\) \(4\)
\(y=3x^2-5x-7\) 35 15 1 −7 −9 −5 5 21

For example, when \(x=-2\),

\[ y=3(-2)^2-5(-2)-7=12+10-7=15. \]

(b) and (c) The required graphs, drawn on the same axes, are shown below. The curve is \(y=3x^2-5x-7\), and the straight line is \(y=-3x-2\).

graph
Scale: 2 cm represents 1 unit on the x-axis and 2 cm represents 5 units on the y-axis. The curve crosses the x-axis at approximately x = −0.9 and x = 2.6; the line meets the curve at x = −1 and x ≈ 1.7.

(d)(i) \(3x^2-5x-7<0\) where the parabola lies below the \(x\)-axis. Reading the intercepts from the graph gives approximately \(-0.9\) and \(2.6\). Hence,

\[ -0.9<x<2.6. \]

(d)(ii) The roots of \(3x^2-2x-5=0\) are the \(x\)-coordinates of the points where the line and curve intersect:

\[ 3x^2-5x-7=-3x-2 \] \[ 3x^2-2x-5=0. \] From the graph,

\[ x=-1.0\quad\text{or}\quad x\approx1.7. \]

Indeed, \(3x^2-2x-5=(3x-5)(x+1)\), so the exact roots are \(x=-1\) and \(x=\frac53\).

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