(a) Copy and complete the table for \(y = 3x^{2} - 5x - 7\) x -3 -2 -1 0 1 2 3 4 \(y = 3x^{2} - 5x - 7\) 35 -7 -9 5 (b) Using a scale of 2cm = 1 unit along ...
Assessment:WAEC SSCE - General Mathematics - 1996 (Essay)Subject:General Mathematics
(a) Copy and complete the table for \(y = 3x^{2} - 5x - 7\)
x
-3
-2
-1
0
1
2
3
4
\(y = 3x^{2} - 5x - 7\)
35
-7
-9
5
(b) Using a scale of 2cm = 1 unit along the x- axis and 2cm = 5 units along the y- axis, draw the graph of \(y = 3x^{2} - 5x - 7\).
(c) On the same axis, draw the graph of \(y + 3x + 2 = 0\).
(d) From your graph, find the : (i) range of values of x for which \(3x^{2} - 5x - 7 < 0\) ; (ii) roots of the equation \(3x^{2} - 2x - 5 = 0\).
(a) For \(y=3x^{2}-5x-7\), the completed table is:
\(x\)
\(-3\)
\(-2\)
\(-1\)
\(0\)
\(1\)
\(2\)
\(3\)
\(4\)
\(y=3x^2-5x-7\)
35
15
1
−7
−9
−5
5
21
For example, when \(x=-2\),
\[
y=3(-2)^2-5(-2)-7=12+10-7=15.
\]
(b) and (c) The required graphs, drawn on the same axes, are shown below. The curve is \(y=3x^2-5x-7\), and the straight line is \(y=-3x-2\).
Scale: 2 cm represents 1 unit on the x-axis and 2 cm represents 5 units on the y-axis. The curve crosses the x-axis at approximately x = −0.9 and x = 2.6; the line meets the curve at x = −1 and x ≈ 1.7.
(d)(i) \(3x^2-5x-7<0\) where the parabola lies below the \(x\)-axis. Reading the intercepts from the graph gives approximately \(-0.9\) and \(2.6\). Hence,
\[
-0.9<x<2.6.
\]
(d)(ii) The roots of \(3x^2-2x-5=0\) are the \(x\)-coordinates of the points where the line and curve intersect:
\[
3x^2-5x-7=-3x-2
\]
\[
3x^2-2x-5=0.
\]
From the graph,
\[
x=-1.0\quad\text{or}\quad x\approx1.7.
\]
Indeed, \(3x^2-2x-5=(3x-5)(x+1)\), so the exact roots are \(x=-1\) and \(x=\frac53\).
(a) For \(y=3x^{2}-5x-7\), the completed table is:
\(x\)
\(-3\)
\(-2\)
\(-1\)
\(0\)
\(1\)
\(2\)
\(3\)
\(4\)
\(y=3x^2-5x-7\)
35
15
1
−7
−9
−5
5
21
For example, when \(x=-2\),
\[
y=3(-2)^2-5(-2)-7=12+10-7=15.
\]
(b) and (c) The required graphs, drawn on the same axes, are shown below. The curve is \(y=3x^2-5x-7\), and the straight line is \(y=-3x-2\).
Scale: 2 cm represents 1 unit on the x-axis and 2 cm represents 5 units on the y-axis. The curve crosses the x-axis at approximately x = −0.9 and x = 2.6; the line meets the curve at x = −1 and x ≈ 1.7.
(d)(i) \(3x^2-5x-7<0\) where the parabola lies below the \(x\)-axis. Reading the intercepts from the graph gives approximately \(-0.9\) and \(2.6\). Hence,
\[
-0.9<x<2.6.
\]
(d)(ii) The roots of \(3x^2-2x-5=0\) are the \(x\)-coordinates of the points where the line and curve intersect:
\[
3x^2-5x-7=-3x-2
\]
\[
3x^2-2x-5=0.
\]
From the graph,
\[
x=-1.0\quad\text{or}\quad x\approx1.7.
\]
Indeed, \(3x^2-2x-5=(3x-5)(x+1)\), so the exact roots are \(x=-1\) and \(x=\frac53\).