Two tools, one coordinate plane

Transformations and vectors occupy the same coordinate plane, but they ask different questions. Transformations ask: how does a shape move, flip, turn, or resize? Vectors ask: how do we describe displacement and prove geometric relationships algebraically? Both appear regularly on IGCSE Mathematics papers, and both reward precision. A vague description of a transformation loses marks just as surely as an incorrect vector expression.

This guide covers the four standard transformations (translation, reflection, rotation, enlargement), then moves into vector geometry. Core candidates need the transformations. Extended candidates need both.

Translation

A translation slides every point of a shape by the same distance in the same direction. It is described by a column vector.

The column vector (3, -2) means "3 units right, 2 units down." The top number is horizontal movement (positive = right, negative = left). The bottom number is vertical movement (positive = up, negative = down).

Key rule: Under a translation, the shape does not change size, orientation, or handedness. Every length and every angle stays identical. Only position changes.

Worked example 1

Triangle P has vertices at (1, 2), (4, 2), and (4, 5). It is translated by the vector (−3, 1). Find the vertices of the image.

  1. Add the vector to each vertex separately.
  2. (1, 2) + (−3, 1) = (−2, 3)
  3. (4, 2) + (−3, 1) = (1, 3)
  4. (4, 5) + (−3, 1) = (1, 6)

The image has vertices (−2, 3), (1, 3), and (1, 6).

Reflection

A reflection flips a shape across a mirror line. Each point and its image are equidistant from the mirror line, on opposite sides.

Mirror lineEffect on (x, y)
x-axis (y = 0)(x, y) becomes (x, −y)
y-axis (x = 0)(x, y) becomes (−x, y)
y = x(x, y) becomes (y, x)
y = −x(x, y) becomes (−y, −x)

For other mirror lines (e.g. x = 3 or y = −1), find the perpendicular distance from each point to the line and plot the image the same distance on the other side.

Describing a reflection: You must state (1) that it is a reflection and (2) the equation of the mirror line. "Reflected" alone is incomplete and loses marks.

Rotation

A rotation turns a shape around a fixed centre by a specified angle in a specified direction.

Three pieces of information define a rotation completely:

  • The centre of rotation (a coordinate)
  • The angle of rotation (in degrees)
  • The direction (clockwise or anticlockwise)

Omitting any one of these in an exam answer costs marks. A 180-degree rotation is the exception: direction is irrelevant because clockwise and anticlockwise produce the same image.

Worked example 2

Point A is at (3, 1). It is rotated 90 degrees anticlockwise about the origin. Find the image.

  1. For a 90-degree anticlockwise rotation about (0, 0): (x, y) becomes (−y, x).
  2. (3, 1) becomes (−1, 3).

Quick reference for rotations about the origin:

Rotation(x, y) becomes
90° anticlockwise(−y, x)
90° clockwise(y, −x)
180°(−x, −y)

Enlargement

An enlargement changes the size of a shape by a scale factor from a fixed centre of enlargement.

To find the image of a point under enlargement with centre C and scale factor k:

  1. Draw the vector from C to the original point.
  2. Multiply that vector by k.
  3. The image is at C plus the new vector.
Scale factorEffect
k > 1Shape gets larger, same side of centre
0 < k < 1Shape gets smaller, same side of centre
k = −1Same size, opposite side of centre (equivalent to 180° rotation)
k < 0Image is on the opposite side of the centre, inverted
Area and volume under enlargement: If lengths are multiplied by k, areas are multiplied by k² and volumes by k³. A scale factor of 3 means the area becomes 9 times larger.

Describing an enlargement

State three things: (1) that it is an enlargement, (2) the scale factor, and (3) the centre of enlargement. Missing any one loses marks.

Combined transformations

Exam questions sometimes ask for the single transformation equivalent to two successive transformations. The approach:

  1. Apply the first transformation to the original shape to get an intermediate image.
  2. Apply the second transformation to the intermediate image to get the final image.
  3. Compare the original shape to the final image and describe the single transformation that maps one to the other.

Not every pair of transformations can be reduced to a single one of the four types. Two reflections in parallel lines produce a translation. Two reflections in intersecting lines produce a rotation. Be prepared to identify these patterns.

Vectors: the Extended tier

Everything below is Extended content. Core candidates can stop here.

Column vectors and notation

A vector has magnitude (length) and direction. In IGCSE Mathematics, vectors are written as column vectors or as bold lowercase letters (a, b) or with an arrow notation (AB with arrow above).

  • The vector from A to B is written as the column vector (change in x, change in y).
  • The magnitude of vector v = (p, q) is |v| = sqrt(p² + q²).
  • A negative vector reverses direction: if AB = a, then BA = −a.

Vector arithmetic

OperationRuleExample with a = (2, 3) and b = (−1, 4)
AdditionAdd corresponding componentsa + b = (1, 7)
SubtractionSubtract corresponding componentsa - b = (3, −1)
Scalar multiplicationMultiply each component3a = (6, 9)

Position vectors

The position vector of a point P is the vector from the origin O to P. If P = (5, −2), then the position vector of P is (5, −2).

The vector from A to B can be found using position vectors: AB = OB - OA. This is the most reliable method when coordinates are given.

Worked example 3

A has position vector (1, 3) and B has position vector (7, −1). Find the vector AB and the midpoint M of AB.

  1. AB = OB - OA = (7, −1) - (1, 3) = (6, −4).
  2. The midpoint M has position vector OM = OA + (1/2)AB = (1, 3) + (3, −2) = (4, 1).

Alternatively, M = ((1+7)/2, (3+(−1))/2) = (4, 1).

Expressing vectors in terms of base vectors

Many IGCSE vector questions provide a diagram where OA = a and OB = b, then ask you to express other vectors in terms of a and b. The method is always the same: trace a path from start to finish using known vectors.

Worked example 4

In triangle OAB, OA = a and OB = b. M is the midpoint of AB. Express OM in terms of a and b.

  1. Find AB: AB = AO + OB = −a + b = b - a.
  2. M is the midpoint of AB, so AM = (1/2)AB = (1/2)(b - a).
  3. OM = OA + AM = a + (1/2)(b - a) = a + (1/2)b - (1/2)a = (1/2)a + (1/2)b.

So OM = (1/2)(a + b).

Proving collinearity

Three points X, Y, Z are collinear (lie on the same straight line) if XY is a scalar multiple of XZ. If XY = k(XZ) for some scalar k, then Y lies on the line through X and Z.

Worked example 5

OA = a, OB = b. Point P lies on OA such that OP = (2/3)a. Point Q lies on AB such that AQ = (2/3)AB. Show that O, Q, and some other relevant point are collinear, or find OQ.

  1. AB = b - a.
  2. AQ = (2/3)(b - a).
  3. OQ = OA + AQ = a + (2/3)(b - a) = a + (2/3)b - (2/3)a = (1/3)a + (2/3)b.

If another point R has position vector that is a scalar multiple of (1/3)a + (2/3)b, then O, Q, and R are collinear.

Finding ratios

If P divides AB in the ratio m : n, then:

  • AP = (m/(m+n)) AB
  • OP = OA + AP = OA + (m/(m+n))(OB - OA)

This formula handles any ratio problem on the IGCSE paper.

Common mistakes

MistakeWhy it loses marksFix
Incomplete transformation description"A rotation of 90°" without centre or direction is worth zero for the description marks.Use a checklist: translation (vector), reflection (mirror line equation), rotation (centre, angle, direction), enlargement (centre, scale factor).
Confusing the direction of a vectorAB and BA point opposite ways. Writing OA - OB instead of OB - OA reverses the answer.Always read the letters in order. AB means "from A to B," calculated as OB - OA.
Forgetting negative scale factors flip the imageA scale factor of -2 places the image on the opposite side of the centre. Students who ignore the sign place it incorrectly.Plot the centre first. Draw the ray from centre through the original point. Extend it beyond the centre for negative factors.
Dropping the vector arrow or bold in workingExaminers may not distinguish scalar from vector quantities if notation is ambiguous.Underline vector letters in handwriting. Always use arrow notation or consistent underlining throughout.
Not simplifying vector expressionsLeaving (2/6)a instead of (1/3)a suggests incomplete understanding.Simplify fractions in vector coefficients as a final step.

Self-check questions

  1. A shape is translated by the vector (−4, 5). If one vertex is at (2, −3), where is its image?
  2. Describe fully the single transformation that maps triangle A with vertices (1, 1), (3, 1), (3, 4) to triangle B with vertices (−1, 1), (−3, 1), (−3, 4).
  3. A point (5, 2) is rotated 90° clockwise about the origin. State the coordinates of the image.
  4. A shape is enlarged with scale factor 2 and centre (1, 1). The original point is (3, 4). Find the image.
  5. If the scale factor of an enlargement is 0.5, what happens to the area of the shape?
  6. Given a = (3, −1) and b = (−2, 5), find 2a + b and |2a + b|.
  7. A has position vector (2, 6) and B has position vector (8, −2). Find the vector AB and the midpoint of AB.
  8. In a triangle OAB, OA = a and OB = b. P is the point on AB such that AP:PB = 1:3. Express OP in terms of a and b.
  9. Points X, Y, Z have position vectors (1, 2), (4, 5), and (7, 8). Show that X, Y, and Z are collinear.
  10. A triangle is reflected in y = x, then reflected in y = −x. Describe the single transformation equivalent to these two reflections.

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TLDR

A concise revision guide to transformations and vectors for Cambridge IGCSE Mathematics (0580), covering translations, reflections, rotations, enlargements, combined transformations, column vectors, position vectors, and vector proofs, with worked examples and self-check questions.