Consider the following half-cell reactions. Al(s) \(\to\) Al3+(aq) + 3e- Cu2+(aq) + 2e- \(\to\) Cu(s) The overall equation for the reaction is

2Al(s) + 3Cu2+(aq) \(\to\) 3Cu(s) + 2Al3+(aq)

Al(s) + Cu2+(aq) \(\to\) Al3+(aq) + Cu(s)

2Al(s) + Cu2+(aq) \(\to\) 2Al(aq) + Cu(s)

2Al(s) + 3Cu2+(aq) \(\to\) 3Cu(s) + 2Al3+(aq)

3Al(s) + 2Cu2+(aq) \(\to\) Cu(s) + 3Al3+(aq)

WAEC SSCE - Chemistry - 2016 (Objective)

Question 1 Report

On evaporation to dryness, 350³ of saturated solution of salt Z gave 55.5g of salt. What is the solubility of the salt? [Z = 101]

1.57 moldm^-3 Correct answer

3.14 moldm^-3

6.28 moldm^-3

12.56 moldm^-3

Answer Details

The solubility of a salt is defined as the maximum amount of solute that can be dissolved in a given amount of solvent at a specified temperature and pressure. Given that 350³ of saturated solution of salt Z gave 55.5g of salt. We can find the solubility of the salt using the formula: Solubility = Mass of solute / Volume of solution First, we need to convert the given mass of salt to moles using its molar mass: Molar mass of Z = 101g/mol Number of moles of Z = 55.5g / 101g/mol = 0.5495 mol Now, we can calculate the volume of the solution using the given volume of 350³: Volume of solution = 350³ = 0.35 dm³ Substituting the values into the formula, we get: Solubility = 0.5495 mol / 0.35 dm³ = 1.57 moldm^-3 Therefore, the solubility of salt Z is 1.57 moldm^-3.

Read lesson note on Solubility Of Substances (Ghana Only) (WAEC)

Read lesson note on Kinetic Theory Of Matter And Gas Laws (JAMB)






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