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WAEC SSCE - General Mathematics - 1988 (Objective)

Question 1 Report

Find the 8th term of the A.P -3, -1, 1 ......
Answer Details
In an arithmetic progression (A.P.), each term is obtained by adding a fixed constant (d) to the previous term. The common difference (d) between any two consecutive terms of an A.P. is constant. In this A.P., the first term is -3 and the common difference is 2, since each term is obtained by adding 2 to the previous term (-3 + 2 = -1, -1 + 2 = 1, and so on). To find the 8th term, we can use the formula: nth term = a + (n-1)d where nth term is the term we want to find (in this case, the 8th term), a is the first term, n is the position of the term we want to find, and d is the common difference. Substituting the given values, we get: 8th term = -3 + (8-1)*2 8th term = -3 + 14 8th term = 11 Therefore, the 8th term of the A.P. -3, -1, 1...... is 11.
Read lesson note on Sequence And Series (WAEC)
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