WAEC SSCE - Physics - 2004 (Objective)

Question 1 Report

A charge of 1.6 x 10^-10C is placed in a uniform electric field of intensity 2.0 x 10⁵ NC^-1. calculate the magnitude of the electric force exerted on the change

3.2 x 10⁵N

1.8 x 10⁵N

3.2 x 10^-5N

1.8 x 10^-5N

Answer Details

The magnitude of electric force can be calculated using the formula: Electric force (F) = charge (Q) x electric field intensity (E) Substituting the given values, we get: F = Q x E F = (1.6 x 10^-10 C) x (2.0 x 10^5 NC^-1) F = 3.2 x 10^-5 N Therefore, the magnitude of the electric force exerted on the charge is 3.2 x 10^-5 N. The correct option is (C) 3.2 x 10^-5 N.






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