WAEC SSCE - Chemistry - 2021 (Objective)

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Question 2 Report

What would be observed when aqueous ammonia is added in drops and then in excess to a solution of copper(II) ions?

blue precipitate is formed which is soluble in excess ammonia

brick red precipitate is produced which is insoluble in excess ammonia

which precipitate is formed which is excess in ammonia

green precipitate is formed which is insoluble in excess ammonia

Answer Details

When aqueous ammonia is added in drops to a solution of copper(II) ions, a pale blue precipitate is formed. This is due to the formation of a complex ion known as tetraamminecopper(II) [Cu(NH3)4]2+. This complex ion has a blue color and is responsible for the color change observed in the solution. If more aqueous ammonia is added to the solution, the blue precipitate dissolves due to the formation of a soluble complex ion known as pentamminecopper(II) [Cu(NH3)5]2+. This solution will appear deep blue in color. Therefore, when excess aqueous ammonia is added to a solution of copper(II) ions, a deep blue solution of pentamminecopper(II) complex ion is formed, and there will be no precipitate. It is important to note that the color changes observed are due to the formation of complex ions and not due to the formation of a new substance.

Read lesson note on Acids, Bases And Salts (Ghana Only) (WAEC)

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Question 3 Report

The collision between ideal gas molecules are considered to be perfectly elastic because

they collide without losing energy

they move randomly in a straight line

their average kinetic energy is variable

the distance between them is large compared to their size

Answer Details

The collision between ideal gas molecules are considered to be perfectly elastic because they collide without losing energy. In an ideal gas, the molecules are considered to be point masses that move randomly in a straight line and collide with each other and the walls of the container. The collisions are perfectly elastic, meaning that no energy is lost during the collision. During a collision between ideal gas molecules, energy can be transferred from one molecule to another, but the total energy of the system remains constant. This is because the molecules are not considered to have any internal energy, such as rotational or vibrational energy, that could be lost during a collision. The lack of energy loss during collisions is a fundamental assumption of the kinetic theory of gases, which describes the behavior of gases at the molecular level. This assumption allows us to calculate the properties of gases, such as pressure, volume, and temperature, using simple equations based on the average kinetic energy of the gas molecules. Therefore, the collision between ideal gas molecules are considered to be perfectly elastic because they collide without losing energy.

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Question 4 Report

Under which conditions of pressure (p) and temperature (T) would the volume of an inflated ballon increase? When

P and T are increased

both T and P are decreased

T is increased and P is decreased

T is decreased and P is increased

Answer Details

Read lesson note on Kinetic Theory Of Matter And Gas Laws (JAMB)

Read lesson note on Energy Changes (JAMB)

Energy Changes

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Question 5 Report

The hydrolysis of proteins by diluting mineral acids produces

sucrose

glucose

amino acids

fatty acids

Answer Details

The hydrolysis of proteins by diluting mineral acids breaks down proteins into their constituent building blocks, which are called amino acids. Proteins are large, complex molecules made up of long chains of amino acids that are linked together by peptide bonds. Hydrolysis is a process in which a molecule is broken down by the addition of a water molecule. In the case of proteins, hydrolysis occurs when the peptide bonds between the amino acids are broken by the addition of water. This process is catalyzed by dilute mineral acids, such as hydrochloric acid (HCl). The result of this reaction is the breakdown of proteins into individual amino acids, which are then available for use by the body to synthesize new proteins or to be used as a source of energy. Therefore, the correct answer is (C) amino acids. Sucrose, glucose, and fatty acids are not the products of protein hydrolysis. Sucrose is a disaccharide made up of glucose and fructose, while glucose is a simple sugar that is a component of many carbohydrates. Fatty acids are the building blocks of lipids, which are a different class of biomolecules.

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Read lesson note on Periodic Chemistry (Ghana Only) (WAEC)

Energy And Energy Changes

Periodic Chemistry (Ghana Only)

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Question 6 Report

The alkanol represented by the structure below is?

primary and dihydric

secondary and monohydric

tertiary and dihydric

secondary and dihydric

Answer Details

Read lesson note on Periodic Chemistry (Ghana Only) (WAEC)

Periodic Chemistry (Ghana Only)

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Question 7 Report

What number of moles of oxygen would exert a pressure of 10 atm at 320 K in an 8.2 dm\(^{2}\) cylinder?

[R = 0.082 atm dm\(^{3}\) mol\(^{-1}\) K\(^{-1}\)]

0.32

1.56

3.13

31.25

Answer Details

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Question 8 Report

Electrovalent compounds normally ------------

have low boiling points

have mobile electrons

conduct electricity in the solid state

dissolve in polar solvent

Answer Details

Read lesson note on Oxidation And Reduction (JAMB)

Read lesson note on Chemical Equilibria (JAMB)

Oxidation And Reduction

Chemical Equilibria

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Question 9 Report

Which of the following pairs of compounds would form a precipitate when their aqueous solutions are mixed?

NaCl and KNO\(_{3}\)

KCL and NaNO\(_{3}\)

K\(_{2}\)SO\(_{4}\) and BaCl\(_{2}\)

NH\(_{4}\)NO\(_{3}\) and CO\(_{3}\)

Answer Details

Read lesson note on Acids, Bases And Salts (Ghana Only) (WAEC)

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Question 10 Report

Consider the structure below

How many carbon atoms does the parent chain contain?

Answer Details

The parent chain in the given structure contains 5 carbon atoms. The parent chain is the longest continuous chain of carbon atoms in a molecule, and it is used as the basis for naming organic compounds. In the given structure, the longest continuous chain of carbon atoms starts from the leftmost carbon atom and extends to the rightmost carbon atom, with a total of 5 carbon atoms. The other carbon atoms in the molecule are attached to the parent chain as substituents. In this case, there are two substituents, each consisting of a single carbon atom with a methyl (-CH3) group attached. Therefore, the parent chain in the given structure contains 5 carbon atoms.

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Chemistry Of Carbon Compounds (Nigeria Only)

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Question 11 Report

Which of the following scientists discovered the electrons?

Joseph J. Thompson

James Chadwick

Amedeo Avogadro

Ernest Rutherford

Answer Details

Joseph J. Thomson discovered electrons. Joseph J. Thomson was a British physicist who conducted a series of experiments in the late 19th century to study the nature of electric discharge in gases. In 1897, he performed a famous experiment involving cathode rays, which are beams of electrons that travel from the negatively charged electrode (cathode) to the positively charged electrode (anode) in a vacuum tube. Thomson observed that cathode rays could be deflected by magnetic and electric fields, indicating that they were negatively charged particles. He proposed that these particles were a fundamental component of all atoms and called them "corpuscles," which later became known as electrons. Thomson's discovery of the electron revolutionized our understanding of atomic structure and led to the development of modern physics. He was awarded the Nobel Prize in Physics in 1906 for his work on the conduction of electricity in gases. Therefore, Joseph J. Thomson discovered electrons.

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Question 12 Report

How many coulombs of electricity would liberate 1.08g of Ag from a solution of silver salt?

[Ag = 108.0; 1F = 96500 C]

96500 C

9650 C

965 C

9.65 C

Answer Details

To calculate the number of coulombs of electricity required to liberate 1.08g of Ag from a silver salt solution, we need to use Faraday's laws of electrolysis, which state that the amount of a substance produced by electrolysis is directly proportional to the quantity of electricity passed through the electrolyte. The formula for calculating the amount of electricity required to liberate a certain amount of a substance is: Quantity of electricity = (Mass of substance / Equivalent weight) × 96500 The equivalent weight of Ag is equal to its atomic weight divided by its valency. Since the valency of Ag is 1, the equivalent weight is equal to its atomic weight, which is 108.0 g/mol. Using the above formula, we get: Quantity of electricity = (1.08 g / 108.0 g/mol) × 96500 C/mol Quantity of electricity = 965 C Therefore, the number of coulombs of electricity required to liberate 1.08g of Ag from a silver salt solution is 965 C. In summary, option C is the correct answer.

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Electrolysis

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Question 13 Report

Which of the following gasses is highly soluble in water at room temperature

ammonia

carbon (IV) oxide

chlorine

nitrogen

Answer Details

The solubility of a gas in water is determined by several factors, including temperature, pressure, and the nature of the gas and the solvent. At room temperature, the gas that is highly soluble in water is ammonia (NH\(_{3}\)). Ammonia is a polar molecule, meaning it has regions of positive and negative charge, and it readily dissolves in water due to the strong hydrogen bonding interactions between the ammonia molecule and the water molecules. In contrast, carbon (IV) oxide (CO\(_{2}\)) is only slightly soluble in water, and it is often used as a reference for measuring the solubility of other gases. Chlorine (Cl\(_{2}\)) is highly reactive and toxic, and it is not very soluble in water at room temperature. Nitrogen (N\(_{2}\)) is an unreactive gas and is only slightly soluble in water. So, of the gases listed, ammonia is the most soluble in water at room temperature.

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Oxidation And Reduction

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Question 14 Report

The isotopes of neon are represented by the symbols \(^{20}\)\(_{x}\) Ne, \(^{21}\) \(_{y}\) Ne, and \(^{22}\) \(_{z}\) Ne. The relationship between x, y, and z is?

x > y > z

x < y < z

x = y= z

x < z < y

Answer Details

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Structure Of The Atom

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Question 15 Report

The basic property of salts used as drying agents is by?

efforescence

high melting point

hygroscopy

low solubility

Answer Details

The property of salts that makes them effective drying agents is their ability to absorb moisture from their surroundings, a characteristic called hygroscopy. When exposed to an environment with high humidity, the salt molecules attract and hold onto water molecules, effectively removing moisture from the surrounding area. This makes them useful for drying out materials such as solvents or wet surfaces. Salts with high solubility, low melting point, or efflorescence are not typically effective as drying agents because they tend to absorb water and dissolve rather than removing it from the environment. Salts with low solubility, on the other hand, tend to be more effective drying agents as they can absorb more moisture without dissolving.

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Acids, Bases And Salts

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Question 16 Report

Which of the following statements about elements in Group VII is correct?

Br\(_{2}\) will oxidize CI\(^{-}\)

F\(_{2}\) has the least tendency to be reduced

Cl\(_{2}\) will oxidize I\(^{-}\)

l\(_{2}\) is a stronger oxidizing agent than F\(_{2}\)

Answer Details

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Oxidation And Reduction

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Question 17 Report

Protons and electrons are called fundamental particles because they----------

are indivisible

have different charges

are the lightest particles

are found in all matter

Answer Details

Protons and electrons are called fundamental particles because they are considered to be the building blocks of matter. They cannot be divided into smaller particles and still retain their unique properties. Additionally, protons have a positive charge and electrons have a negative charge, which makes them essential for creating stable atoms. Finally, protons and electrons are found in all matter, meaning that they are fundamental to the composition of the universe. Therefore, all of the given options are correct, and each contributes to the overall understanding of why protons and electrons are fundamental particles.

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Structure Of The Atom

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Question 18 Report

Study the graphs below and use them to answer the question below

Which of the graphs illustrates the variation of the pH of a given volume of strong acid solution (y-axis) with the volume of strong base titrated against its (x-axis)?

III

Answer Details

Read lesson note on Solubility Of Substances (Ghana Only) (WAEC)

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Question 19 Report

The Bohr model of the atom proposed the existence of

the nucleus

electron shells

nucleons

neutrons

Answer Details

The question is asking about the Bohr model of the atom and what it proposed. The Bohr model of the atom was proposed by Niels Bohr in 1913. It is a model that describes the structure of the atom, with the nucleus at the center and electrons orbiting the nucleus in specific energy levels or shells. Therefore, the answer to the question is "electron shells". The Bohr model proposed the existence of electron shells, which are specific energy levels that electrons occupy around the nucleus of an atom. These shells are quantized, meaning that they can only have certain energy values, and electrons can move between them by absorbing or releasing energy. Option A, "the nucleus", is not specific to the Bohr model and was already known to exist before the development of the Bohr model. Option C, "nucleons", refers to the collective term for the particles in the nucleus (protons and neutrons), which are not part of the Bohr model's description of the electron shells. Option D, "neutrons", is a type of nucleon, but again, it is not part of the Bohr model's description of the electron shells.

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Question 20 Report

The following ions have the same electron configuration except

\(_{8}\)O, \(_{12}\)Mg, \(_{13}\)AI, \(_{17}\)CI

CI\(^{-}\)

O\(^{2-}\)

Mg\(^{2+}\)

AI\(^{3+}\)

Answer Details

Read lesson note on Atomic Structure And Bonding (JAMB)

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Question 21 Report

Student X titrated 25 cm\(^{3}\) of Na\(_{2}\)CO\(^{3}\) with 0.1 mol dm\(^{-3}\) HCI, using methyl orange as indicator. Student Y carried out the same exercise but used phenolphthalein as an indicator. Which of the following statements about the titration is true?

hydrogen chloride gas was released in the reactions in both titrations

the titer values obtained from the titration are equal

the tirer value obtained by X is twice that of Y

the titer value obtained by Y is twice that of X

Answer Details

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Stoichiometry And Chemical Reactions

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Question 22 Report

A coordinate covalent bond could be formed between?

NH\(_{3}\) and PCl\(_{3}\)

BCl\(_{3}\) and AlCl\(_{3}\)

BCl\(_{3}\) and NH\(_{3}\)

H\(^{+}\) and AlCl\(_{3}\)

Answer Details

Read lesson note on Chemical Bonds (Nigeria Only) (WAEC)

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Question 23 Report

Which of the following half reaction equations represent the reaction at the cathode

A\(^{3+_{(aq)}}\)+3e\(^{-}\) \(\rightarrow\) A\(_{(s)}\)

B\(^{2+_{(aq)}}\)+2e\(^{-}\) \(\rightarrow\) B\(_{(s)}\)

A\(_{(s)}\) \(\rightarrow\) \(^{3+_{(aq)}}\)+3e\(^{-}\)

B\(_{(s)}\) \(\rightarrow\) B\(^{2+_{(aq)}}\) + 2e\(^{-}\)

Answer Details

In an electrochemical cell, the cathode is the electrode where reduction occurs. Reduction is the gain of electrons by a species. So, the half-reaction equation that involves the gain of electrons is the reaction at the cathode. Option B represents the reaction at the cathode because it involves the gain of two electrons, which is a reduction half-reaction. The species B\(^{2+}\) is being reduced to B\(_{(s)}\), which means that B\(^{2+}\) is gaining two electrons to become a neutral atom of B. Option A is not the reaction at the cathode because it involves the oxidation of A\(_{(s)}\) to A\(^{3+}\). This is an oxidation half-reaction, and it occurs at the anode. Option C is not the reaction at the cathode because it involves the reduction of A\(^{3+}\) to A\(_{(s)}\). This is a reduction half-reaction, but it occurs at the anode in an electrolytic cell. Option D is not the reaction at the cathode because it involves the oxidation of B\(_{(s)}\) to B\(^{2+}\). This is an oxidation half-reaction, and it occurs at the anode. In summary, option B represents the reaction at the cathode because it involves the gain of two electrons, which is a reduction half-reaction.

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Question 24 Report

Potassium trioxonitrate (V) can be obtained from its solution by----------

distillation

evapoartion

crystallization

filtration

Answer Details

Read lesson note on Acids, Bases And Salts (Ghana Only) (WAEC)

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Question 25 Report

The 25°C evaporation of a 100 cm\(^{3}\) solution of K\(_{2}\)CO\(_{3}\) to dryness gave 14g of the salt. What is the solubility of K\(_{2}\)CO\(_{3}\) at 25°25C? [K\(_{2}\)CO\(_{3}\) = 138]

0.01 mol dm\(^{-3}\)

0.101 mol dm\(^{-3}\)

1.01 mol dm \(^{-3}\)

10.0 mol dm\(^{-3}\)

Answer Details

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Question 26 Report

A molecular of phosphorus is

diatomic

triatomic

tetraatomic

monoatomic

Answer Details

A molecule is a group of two or more atoms held together by chemical bonds. A monoatomic molecule is a molecule made up of a single atom. Phosphorus, which has the chemical symbol P and atomic number 15, can exist in several allotropes, including white, red, and black phosphorus. At standard temperature and pressure, white phosphorus is the most stable allotrope and exists as P\(_{4}\) molecules, which are tetraatomic. Therefore, the correct answer is tetraatomic.

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Structure Of The Atom

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Question 27 Report

Study the graphs below and use them to answer the question below

Which of the graphs illustrates the variation of the solubility of a salt in water (y-axis), with an increase in temperature (x-axis) if the dissolution process is exothermic?

III

Answer Details

Read lesson note on Solubility Of Substances (Ghana Only) (WAEC)

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Question 28 Report

The energy profile diagram illustrates-------------

an endothermic reaction

an exothermic reaction

a spontaneous reaction

a redox reaction

Answer Details

An energy profile diagram is a graphical representation of the energy changes that occur during a chemical reaction. It shows the energy of the reactants, the energy of the products, and the energy changes that occur during the course of the reaction. The x-axis of the energy profile diagram represents the reaction coordinate, which is a measure of the progress of the reaction from the reactants to the products. The y-axis represents the energy of the system, usually in units of joules or kilojoules per mole. An endothermic reaction is a reaction that absorbs heat from the surroundings, resulting in a positive change in enthalpy (?H>0). In an energy profile diagram for an endothermic reaction, the energy of the products is higher than the energy of the reactants, and the reaction requires an input of energy to proceed. The activation energy, which is the energy required to initiate the reaction, is represented by a peak in the diagram. In contrast, an exothermic reaction is a reaction that releases heat to the surroundings, resulting in a negative change in enthalpy (?H<0). In an energy profile diagram for an exothermic reaction, the energy of the products is lower than the energy of the reactants, and the reaction releases energy as it proceeds. The activation energy is also represented by a peak in the diagram. A spontaneous reaction is a reaction that occurs naturally without the need for an input of energy. In an energy profile diagram for a spontaneous reaction, the energy of the products is lower than the energy of the reactants, and the reaction releases energy as it proceeds. However, the activation energy may still be required to initiate the reaction. A redox reaction is a reaction that involves a transfer of electrons from one reactant to another. An energy profile diagram for a redox reaction may show the energy changes associated with the transfer of electrons, but it is not specific to redox reactions. In summary, an energy profile diagram illustrates the energy changes that occur during a chemical reaction, and can be used to identify whether the reaction is endothermic or exothermic, spontaneous or non-spontaneous. Therefore, the answer to this question is either (a) an endothermic reaction or (b) an exothermic reaction, depending on the specific diagram being referred to.

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Energy Changes

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Question 29 Report

Which of the following cell notations represent the diagram

B\(^{2}\)+/B/ /A/A\(^{3+}\)

A\(^{3+}\) /A/ /B/B\(^{2+}\)

B/B\(^{2+}\)/ /A/\(^{3+}\)

A/A\(^{3+}\)/ /B\(^{2+}\)/B

Answer Details

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Oxidation And Reduction

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Question 30 Report

The most common method of preparing insoluble salts is by

filtration

decomposition

neutralization

double decomposition

Answer Details

The most common method of preparing insoluble salts is by double decomposition. Double decomposition is a chemical reaction that involves the exchange of ions between two ionic compounds. In this reaction, the cations and anions of two different compounds switch places, resulting in the formation of two new compounds. When one of the products of this reaction is an insoluble salt, it can be separated from the solution by filtration. For example, suppose we want to prepare the insoluble salt lead(II) chloride (PbCl\(_2\)). We can do this by reacting lead(II) nitrate (Pb(NO\(_3\))\(_2\)) with sodium chloride (NaCl): Pb(NO\(_3\))\(_2\) + 2 NaCl → PbCl\(_2\) + 2 NaNO\(_3\) In this reaction, the lead(II) cation (Pb\(^{2+}\)) and the chloride anion (Cl\(^-\)) switch places, resulting in the formation of lead(II) chloride and sodium nitrate (NaNO\(_3\)), which remains soluble in water. The lead(II) chloride is insoluble in water and will precipitate out of the solution. We can then isolate the solid PbCl\(_2\) by filtration. Therefore, double decomposition is the most common method of preparing insoluble salts, as it allows us to precisely control the reaction conditions and obtain the desired product with high purity.

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Acids, Bases And Salts

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Question 31 Report

What is the empirical formula of a hydrocarbon containing 0.160 moles of carbon and 0.640 moles of hydrogen

CH\(_{2}\)

CH\(_{3}\)

CH\(_{4}\)

C\(_{2}\)H\(_{4}\)

Answer Details

To determine the empirical formula of a hydrocarbon, we need to know the number of moles of each element present in the compound. In this case, we are given that the hydrocarbon contains 0.160 moles of carbon and 0.640 moles of hydrogen. To find the empirical formula, we need to determine the simplest whole-number ratio of the atoms in the compound. We can start by dividing the number of moles of each element by the smallest number of moles to obtain a ratio of the atoms in the compound. In this case, the smallest number of moles is 0.160, which corresponds to the number of moles of carbon. Dividing the number of moles of hydrogen by 0.160, we get: 0.640 mol H / 0.160 mol C = 4 mol H/mol C This means that there are four times as many hydrogen atoms as carbon atoms in the compound. Therefore, the empirical formula of the hydrocarbon is CH\(_{4}\), which corresponds to one carbon atom and four hydrogen atoms. So, the answer is option (C) CH\(_{4}\).

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Stoichiometry And Chemical Reactions

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Question 32 Report

Which of the following oxide causes acid rain?

H\(_{2}\)O\(_{2}\)

NO\(_{2}\)

Answer Details

The oxide that causes acid rain is NO\(_{2}\). Acid rain is a type of rain that has a low pH value (below 5.6) due to the presence of certain pollutants in the air. These pollutants, such as sulfur dioxide and nitrogen oxides, can react with water in the atmosphere to form acids that fall to the ground as acid rain. Among the options given, NO\(_{2}\) is the only oxide that contains nitrogen, which is a major contributor to acid rain. When NO\(_{2}\) is released into the atmosphere, it reacts with water to form nitric acid, which is a strong acid that can lower the pH of rainwater. Therefore, the correct answer is option D: NO\(_{2}\).

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Acids, Bases And Salts

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Question 33 Report

The region around the nucleus where electrons can be located is called?

a spectra

an orbital

a quanta

a field

Answer Details

The region around the nucleus where electrons can be located is called an orbital. An orbital is a three-dimensional region in space where an electron is most likely to be found. The electrons in an atom occupy specific orbitals, which are determined by the energy of the electron and its distance from the nucleus. The electrons in an orbital are said to be in a specific energy state and occupy a particular energy level. The shape and size of an orbital depend on the energy of the electron and the number of electrons in the orbital. In simple terms, an orbital is like a cloud around the nucleus that defines the region where an electron can be found.

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Question 34 Report

The enthalpy change of the reaction is------------

E\(_{A}\)

E\(_{B}\)

E\(_{C}\)

E\(_{D}\)

Answer Details

Read lesson note on Energy Changes (JAMB)

Energy Changes

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Question 35 Report

If humid air is polluted by chlorine discharged, the air can be restored by sprinkling

solid MnO\(_{2}\)

acidified KMnO\(_{4}\)

acidified FeSO\(_{4}\)

saturated NaCl(aq)

Answer Details

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Chemistry And Industry

Acids, Bases And Salts (Nigeria Only)

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Question 36 Report

Which of the following statements is correct about ionization energy? It

decreases across the periods

results in the formation of an anion

causes Metalic nuclei to disintegrate

decreases down the group

Answer Details

The correct statement about ionization energy is that it decreases down the group. Ionization energy is defined as the energy required to remove an electron from an atom or a positive ion in the gaseous state. The ionization energy of an atom depends on the nuclear charge, the distance between the nucleus and the outermost electron, and the shielding effect of inner electrons. As we move down a group in the periodic table, the number of electron shells increases, and the shielding effect of inner electrons also increases. This means that the outermost electrons are held less tightly by the nucleus and are easier to remove. Therefore, the ionization energy decreases down the group. Conversely, as we move across a period, the number of electron shells remains the same, but the nuclear charge increases. This means that the outermost electrons are held more tightly by the nucleus and require more energy to remove. Therefore, the ionization energy increases across the period. The other options in the question are incorrect. Ionization energy does not result in the formation of an anion, nor does it cause metallic nuclei to disintegrate.

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Question 37 Report

Elements with high ionization energies would-------

lose electrons easily

have large atomic radii

have high effective nuclear charges

have low atomic numbers

Answer Details

Elements with high ionization energies would have high effective nuclear charges. This means that the positively charged nucleus of the atom has a strong hold on its electrons, making it difficult to remove them. The ionization energy is the energy required to remove an electron from an atom. Elements with high ionization energies are therefore less likely to lose electrons easily and become positively charged ions. This can also result in elements having higher electronegativities, which is a measure of an atom's tendency to attract electrons towards it.

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Question 38 Report

Which of the following statements about Group VII elements is correct?

they are present in the same physical state

they are strong reducing agents

their reactivity decreases down the group

they exist as monoatomic molecules

Answer Details

The statement that is correct about Group VII elements (also known as the halogens) is that their reactivity decreases down the group. Group VII elements are located in the periodic table in the 17th column and include fluorine (F), chlorine (Cl), bromine (Br), iodine (I), and astatine (At). These elements have similar chemical and physical properties, including high reactivity. However, as you move down the group, the reactivity of the halogens decreases. This is due to the increase in atomic size and the decrease in effective nuclear charge. The larger size of the atoms makes it harder for the halogens to gain an electron, reducing their reactivity. This trend can be seen in the reactivity of the halogens in different chemical reactions.

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Periodic Chemistry (Ghana Only)

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Question 39 Report

Study the graphs below and use them to answer the question below

Which of the following illustrates the variation of the rate of evolution of gas from a given length of magnesium ribbon (y-axis) with an increase in the concentration of the added (x-axis)?

III

Answer Details

Read lesson note on Kinetic Theory Of Matter And Gas Laws (JAMB)

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Question 40 Report

What is the relative molecular mass of the compound below

[H = 1.0; C = 12.0; O = 16.0]

137

136

Answer Details

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Question 41 Report

The reactivity of fluorine is high because of

its high electronegativity

the small size of the fluorine atom

the availability of d-orbitals

the strong F-F bond

Answer Details

The reactivity of fluorine is high due to its high electronegativity. Electronegativity is the ability of an atom to attract electrons towards itself. Fluorine has the highest electronegativity of all elements, which means that it attracts electrons towards itself more strongly than any other element. This makes fluorine highly reactive, as it tends to form strong bonds with other atoms by either gaining or sharing electrons. In addition to its high electronegativity, the small size of the fluorine atom also contributes to its high reactivity. The small size allows fluorine atoms to approach other atoms very closely, which enhances the strength of the interactions between them. The availability of d-orbitals and the strong F-F bond are not responsible for the high reactivity of fluorine. Therefore, the correct answer is option A: its high electronegativity.

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Question 42 Report

Which of the following pairs of molecules form hydrogen bonds?

C\(_{2}\)H\(_{5}\)OH and CH\(_{3}\)OH

CH\(_{3}\)OH and H\(_{2}\)

H\(_{2}\)S and CH\(_{4}\)

NH\(_{3}\) and SO\(_{2}\)

Answer Details

The pair of molecules that form hydrogen bonds are C\(_{2}\)H\(_{5}\)OH and CH\(_{3}\)OH. A hydrogen bond is a type of chemical bond that forms between a partially positively charged hydrogen atom and a partially negatively charged atom, such as oxygen or nitrogen. In the case of C\(_{2}\)H\(_{5}\)OH and CH\(_{3}\)OH, both molecules contain oxygen atoms, which have a partial negative charge. Additionally, the hydrogen atoms in these molecules are partially positively charged. This creates an opportunity for hydrogen bonding to occur between the oxygen atom in one molecule and the hydrogen atom in another molecule. In contrast, the other pairs of molecules listed do not contain the necessary atoms with partial charges for hydrogen bonding to occur. CH\(_{3}\)OH and H\(_{2}\) do not have any partially charged atoms, while H\(_{2}\)S and CH\(_{4}\) do not contain atoms with the necessary partial charges to form hydrogen bonds. NH\(_{3}\) and SO\(_{2}\) have partially charged atoms, but these atoms do not interact with each other in a way that allows for hydrogen bonding to occur. Therefore, only C\(_{2}\)H\(_{5}\)OH and CH\(_{3}\)OH can form hydrogen bonds.

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Oxidation And Reduction

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Question 43 Report

The ratio of carbon atoms of hydrogen atoms in a hydrocarbon is 1:2. If its molecular mass is 56, what is its molecular formula?

C\(_{3}\)H\(_{6}\)

C\(_{4}\)H\(_{8}\)

C\(_{2}\)H\(_{4}\)

CH\(_{2}\)

Answer Details

In order to determine the molecular formula of the hydrocarbon, we need to use the information given in the question to calculate the number of carbon and hydrogen atoms in the molecule. The ratio of carbon atoms to hydrogen atoms in the hydrocarbon is 1:2, which means that for every one carbon atom, there are two hydrogen atoms. We can represent this ratio using the general formula C\(_{n}\)H\(_{2n}\), where n is the number of carbon atoms in the molecule. Next, we are given the molecular mass of the hydrocarbon, which is 56. To find the value of n, we need to use the molecular formula to calculate the molecular mass. For the general formula C\(_{n}\)H\(_{2n}\), the molecular mass can be calculated using the formula: Molecular mass = n x (atomic mass of carbon) + 2n x (atomic mass of hydrogen) Substituting the values of atomic mass for carbon and hydrogen (12 and 1, respectively), and the given molecular mass of 56, we get: 56 = n x 12 + 2n x 1 Simplifying this equation, we get: 56 = 14n n = 4 Therefore, the molecular formula of the hydrocarbon is C\(_{4}\)H\(_{8}\), which is option B in the question. In summary, the hydrocarbon in the question has a ratio of carbon atoms to hydrogen atoms of 1:2, and a molecular mass of 56. Using this information, we can calculate that its molecular formula is C\(_{4}\)H\(_{8}\).

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Chemistry Of Carbon Compounds (Nigeria Only)

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Question 44 Report

When CuSO\(_{4(aq)}\) is added to Pb(NO\(_{3}\))\(_{2(aq)}\)--------

there would be no visible change

a blue precipitate would be formed

the resulting solution would become colourless

a white precipitate would be formed

Answer Details

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Acids, Bases And Salts

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Question 45 Report

An element, Q, contains 69% of\(^{63}\)Q and 31% of \(^{65}\)Q. What is the relative atomic mass of Q?

63.0

63.6

65.0

69.0

Answer Details

The relative atomic mass (RAM) of an element is the weighted average of the masses of all its isotopes, taking into account their abundance. In this case, we are given the percentage abundance of two isotopes of element Q, and we can use this information to calculate its RAM. To calculate the RAM of Q, we need to multiply the atomic mass of each isotope by its percentage abundance (as a decimal), and then add these values together. The formula for calculating the RAM is: RAM = (mass\(_{63}\)Q x % abundance of\(^{63}\)Q) + (mass\(_{65}\)Q x % abundance of\(^{65}\)Q) The atomic mass of\(^{63}\)Q is 63, and the atomic mass of\(^{65}\)Q is 65. Substituting the given values into the formula, we get: RAM = (63 x 0.69) + (65 x 0.31) RAM = 43.47 + 20.15 RAM = 63.62 Therefore, the relative atomic mass of element Q is 63.62. So, the answer is option (B) 63.6.

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Question 46 Report

How many molecules of oxygen would occupy a volume of 2.24 cm\(^{3}\) at s.t.p?

[Molar volume at s.t.p = 22,400 cm\(^{3}\), Avogadro's number = 6.02 x 10\(^{23}\)]

3.01 x 10\(^{20}\)

3.01 x 10\(^{27}\)

6.02 x 10\(^{19}\)

6.02 x 10\(^{27}\)

Answer Details

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Question 47 Report

The formation of ethene from dehydration of ethanol can be described as-------

an addition reaction

an elimination reaction

an oxidation reaction

a substitution reaction

Answer Details

The dehydration of ethanol to form ethene is a chemical reaction in which water is removed from ethanol, resulting in the formation of ethene. The reaction can be represented as: CH\(_{3}\)CH\(_{2}\)OH → CH\(_{2}\)=CH\(_{2}\) + H\(_{2}\)O This reaction involves the elimination of a molecule of water (H\(_{2}\)O) from ethanol (CH\(_{3}\)CH\(_{2}\)OH) to form ethene (CH\(_{2}\)=CH\(_{2}\)). Such reactions are known as elimination reactions. In elimination reactions, a molecule is removed from a reactant, resulting in the formation of a new product. This is different from addition reactions, in which two or more reactants combine to form a single product, and substitution reactions, in which one atom or group is replaced by another. Therefore, the correct answer is (B) an elimination reaction.

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Chemistry Of Carbon Compounds (Nigeria Only)

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Question 48 Report

What is the concentration of a solution which contains 0.28g of potassium hydroxide in 100 cm\(^{3}\) of solution [KOH = 56]

0.01 mol dm\(^{-3}\)

0.05 mol dm\(^{-3}\)

0.10 mol dm\(^{-3}\)

0.50 mol dm\(^{-3}\)

Answer Details

To calculate the concentration of a solution, we need to know the amount of solute and the volume of the solution. The given amount of potassium hydroxide is 0.28 g and the volume of the solution is 100 cm\(^{3}\) or 0.1 dm\(^{3}\). First, we need to calculate the number of moles of potassium hydroxide in the solution by dividing its mass by its molar mass: Number of moles of KOH = Mass of KOH / Molar mass of KOH = 0.28 g / 56 g/mol = 0.005 mol Then, we can calculate the concentration of the solution in mol dm\(^{-3}\) by dividing the number of moles by the volume of the solution in dm\(^{3}\): Concentration of KOH solution = Number of moles / Volume of solution = 0.005 mol / 0.1 dm\(^{3}\) = 0.05 mol dm\(^{-3}\) Therefore, the concentration of the solution is 0.05 mol dm\(^{-3}\). is the correct answer.

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Question 49 Report

Which of the following species has the largest ionic radius

S\(^{2-}\)

CI\(^{-}\)

K\(^{+}\)

Ca\(^{2+}\)

Answer Details

Among the given species, Ca\(^{2+}\) has the largest ionic radius. Ionic radius is defined as half the distance between the nuclei of two adjacent ions of the same element in a crystal lattice. The ionic radius increases as we move down a group in the periodic table and decreases as we move across a period. Ca\(^{2+}\) has the largest ionic radius among the given species because it has the least nuclear charge compared to the other ions. As we move from left to right in a period, the number of protons in the nucleus increases, resulting in a greater nuclear charge. The greater nuclear charge attracts the electrons more strongly, causing the ionic radius to decrease. In contrast, as we move down a group, the number of electron shells increases, leading to an increase in the size of the ion. Therefore, among the given species, Ca\(^{2+}\) has the largest ionic radius because it has more electron shells and the least nuclear charge, while S\(^{2-}\) has the smallest ionic radius because it has the greatest nuclear charge and the least electron shells.

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Question 50 Report

The activation energy of the reaction is

E\(_{A}\)

E\(_{B}\)

E\(_{C}\)

E\(_{D}\)

Answer Details

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