JAMB UTME - Physics - 2012 | Green Bridge CBT

Question 1 Report

2000cm3 of a gas is collected at 27oC and 700mmHg. What is the volume of the gas at standard temperature and pressure?

1896.5cm3

1767.3cm3

1676.3cm3

1456.5cm3

Answer Details

$V_{2} = \frac{P_{1} V_{1} T_{2}}{P_{2} T_{2}}$

$V_{2} = \frac{700 \times 2000 \times 273}{760 \times 300}$

Read lesson note on Measurements And Units (JAMB)

Measurements And Units

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Question 2 Report

Which of the following factors will affect the velocity of sound?

An increase in the pitch of the sound

An increase in the loudness of the sound

Wind travelling in the same direction of the sound

A change in the atmospheric pressure at constant temperature

Rectilinear Acceleration

Propagation Of Sound Waves

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Question 3 Report

The current output from of an a.c. source is given as I = 10 sin to t. The d.c equivalent of the current is

5.0A

7.1A

10.0A

14.1A

Answer Details

The given equation of current, I = 10 sin ωt represents an alternating current (a.c.) which varies sinusoidally with time. The maximum value of this current is 10A, which occurs when sin ωt = 1. However, the question asks for the DC equivalent of this current, which is the constant value of current that would produce the same amount of heat in a resistor as the given a.c. current. The DC equivalent of an AC current is the root mean square (rms) value of the AC current, which is the square root of the mean of the square of the current over one cycle. For a sinusoidal current, the rms value is given by the formula I_rms = I_max/√2. Substituting the given maximum value of current (10A) into the formula for rms current gives: I_rms = 10A/√2 = 7.07A (approx) Therefore, the DC equivalent of the given AC current is approximately 7.1A, which is option (B) in the answer choices.

Read lesson note on Simple A.C. Circuits (WAEC)

Read lesson note on Propagation Of Sound Waves (JAMB)

Simple A.C. Circuits

Propagation Of Sound Waves

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Question 4 Report

The use of lenses is Not applicable in the

projector

human eye

periscope

telescope

Optical Instruments

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Question 5 Report

A newly charged 12V accumulator can easily start a car whereas eight new dry cells in series with a effective e.m.f. of 12V cannot start the same car because

The current capacity is high

The current capacity is low

it cannot be re-charged

it cannot easily be connected to a car

Current Electricity

Electric Cells

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Question 6 Report

A car starts from rest and moves with a uniform acceleration of 30ms-2 for 20s. Calculate the distance covered at the end of the motion

6km

12km

18km

24km

Answer Details

The distance covered at the end of the motion is 600 meters. The distance covered by an object with uniform acceleration can be calculated using the equation: distance = initial velocity x time + (1/2) x acceleration x time^2 In this case, the initial velocity is 0 (the car starts from rest), the acceleration is 30 m/s^2, and the time is 20 seconds. Plugging in these values, we get: distance = 0 x 20 + (1/2) x 30 x 20^2 distance = 0 + (1/2) x 30 x 400 distance = 600 meters So, the car covers a distance of 600 meters at the end of the 20 seconds of motion.

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Motion

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Question 7 Report

An object moves in a circular path of radius 0.5m with a speed of 1ms-1 What is its angular velocity?

8 rads-1

4 rads-1

2 rads-1

1 rads-1

Answer Details

The angular velocity of an object moving in a circular path is the rate at which the object is rotating around the center of the circle. It is usually measured in radians per second (rad/s). To find the angular velocity of the object in this question, we can use the formula: angular velocity = speed / radius where speed is the speed of the object and radius is the radius of the circular path. Substituting the values given in the question, we get: angular velocity = 1 m/s / 0.5 m which simplifies to: angular velocity = 2 rad/s Therefore, the answer is 2 rads-1.

Read lesson note on Rectilinear Acceleration (WAEC)

Rectilinear Acceleration

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Question 8 Report

A rocket is fired from the earth's surface to a distant planet. By Newton's law of universal gravitation, the force F will

increase as r reduces

increase as G varies

remains constant

increases as r increases

Description Property Of Fields

Gravitational Field

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Question 9 Report

An object of mass 20kg slides down an inclined plane at an angle of 30o to the horizontal. The coefficient of static friction is?
[g = 10ms-2]

0.2

0.3

0.5

0.6

Answer Details

μ=tanθ=tan30

Read lesson note on Friction (JAMB)

Friction

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Question 10 Report

A glass block of thickness 10cm is placed on an object. If an observer views the object vertically, the displacement of the object is

3.33cm

5.00cm

6.67cm

8.50cm

Scalars And Vectors

Position, Distance And Displacement

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Question 11 Report

A balloon whose volume is 300m3 is filled with hydrogen. If the density of air is 1.3 kgm-3, find the upthrust on the balloon. [g = 10ms-2]

3000N

3800N

3900N

4200N

Answer Details

To find the upthrust on the balloon, we need to use the Archimedes' principle which states that an object submerged in a fluid experiences an upward force that is equal in magnitude to the weight of the fluid displaced. In this case, the balloon is not submerged but is filled with hydrogen which is lighter than air. Thus, the upthrust on the balloon is equal to the weight of the air displaced by the balloon. The weight of the air displaced by the balloon is given by the difference between the weight of the air that would fill the same volume as the balloon and the weight of the hydrogen that actually fills the balloon. The weight of air that would fill the same volume as the balloon is given by: mass of air = density of air x volume of balloon mass of air = 1.3 kg/m^3 x 300 m^3 mass of air = 390 kg The weight of the hydrogen that fills the balloon is given by: mass of hydrogen = density of hydrogen x volume of balloon mass of hydrogen = 0.09 kg/m^3 x 300 m^3 mass of hydrogen = 27 kg Therefore, the weight of the air displaced by the balloon is: weight of air = mass of air x acceleration due to gravity weight of air = 390 kg x 10 m/s^2 weight of air = 3900 N The upthrust on the balloon is equal to the weight of the air displaced, which is 3900 N. Therefore, the correct answer is "3900N." Explanation: The upthrust on an object in a fluid is equal to the weight of the fluid displaced by the object. In this case, the balloon filled with hydrogen displaces air, which has a known density. By calculating the weight of air displaced and subtracting the weight of the hydrogen filling the balloon, we can find the upthrust on the balloon. By using the given values and applying Archimedes' principle, we find that the upthrust on the balloon is 3900 N. Therefore, the correct answer is "3900N."

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Pressure

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Question 12 Report

Which of the following is NOT a factor that can increase the rate of evaporation of water in a lake?

increase in the pressure of the atmosphere

rise in temperature

increase in the average speed of the molecules of water

increase in the kinetic energy of the molecules of water

Equilibrium Of Forces

Temperature And Its Measurement

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Question 13 Report

Where can a man place his face to get an enlarged image when using a concave mirror to shave?

Between the centre of curvature and the principal focus

At the principal focus

Between the principal focus and the pole

At the centre of curvature

Answer Details

To get an enlarged image when using a concave mirror to shave, a man can place his face between the principal focus and the pole of the mirror. A concave mirror has a reflective surface that curves inward like the inside of a bowl. When an object is placed in front of a concave mirror, the mirror reflects light rays that converge and meet at a point called the "focal point" or "principal focus". The distance between the mirror and the focal point is called the "focal length". When a man places his face between the principal focus and the pole of the concave mirror, the mirror forms a virtual, upright, and enlarged image of his face behind the mirror. The image is larger than the actual size of his face because the mirror bends and converges the light rays in such a way that they create a magnified image. If the man places his face at the principal focus or beyond, the mirror will form a real and inverted image of his face, which will be smaller than the actual size of his face. Therefore, the correct answer is option (C) between the principal focus and the pole.

Read lesson note on Electrostatics (JAMB)

Electrostatics

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Question 14 Report

A pinhole camera is placed 300m in front of a building so that the image is formed on a screen 5cm from the the pinhole. If the image is 2.5cm high, the height of the building will be

25m

50m

100m

150m

Answer Details

To find the height of the building, we can use the principle of similar triangles. The ratio of the height of the building to the distance from the pinhole to the building is equal to the ratio of the height of the image to the distance from the pinhole to the screen. So, we can write the following equation: (height of building) / (distance from pinhole to building) = (height of image) / (distance from pinhole to screen) Plugging in the given values, we get: (height of building) / 300m = 2.5cm / 5cm Solving for the height of the building, we get: (height of building) = (2.5cm / 5cm) * 300m Since 1 meter is equal to 100 cm, we can convert the answer to meters: (height of building) = (2.5 / 5) * 300 * (100 cm/m) = 150m So, the height of the building is 150 meters.

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Structure Of The Nucleus

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Question 15 Report

I. Rays of light travel from a less dense medium to a denser medium. II. The Angle of incidence is greater than critical angle. III. Rays of light travel from a denser medium to a less dense medium. Which of the statements above are conditions for total internal reflection to occur?

I & II only

I & III only

II & III only

II only

Refraction Of Light Through Plane And Curved Surfaces

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Question 16 Report

If a freely suspended object is pulled to one side and released, it oscillates about the point of suspension because the

acceleration is directly proportional to the displacement

motion is directed away from the equilibrium point

acceleration is directly proportional to the square of the displacement

velocity is minimum at the equilibrium ponit

Answer Details

If a freely suspended object is pulled to one side and released, it oscillates about the point of suspension because of the property of the object called "restoring force". Restoring force refers to any force that tends to bring an object back to its equilibrium position when it is displaced. When an object is pulled to one side and released, it is displaced from its equilibrium position. The object then experiences a restoring force that pulls it back towards the equilibrium position. This restoring force is proportional to the displacement of the object from its equilibrium position. As a result, the object oscillates back and forth about its equilibrium position. The oscillation continues until all the energy transferred to the object during the initial displacement is dissipated by frictional forces and the object comes to rest. Therefore, the correct answer is option (A) acceleration is directly proportional to the displacement.

Read lesson note on Equilibrium Of Forces (WAEC)

Equilibrium Of Forces

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Question 17 Report

A conductor of length 1m moves with a velocity of 50ms-1 at an angle of 30o to the direction of a uniform magnetic field of flux density 1.5Wbm-2. What is the e.m.f induced in the conductor?

37.5V

50.5V

75.0V

80.5V

Answer Details

The electromotive force (e.m.f) induced in a conductor moving in a magnetic field can be calculated using Faraday's law of electromagnetic induction, which states that the e.m.f induced in a conductor is equal to the rate of change of the magnetic flux through the conductor. The magnetic flux can be calculated as the product of the magnetic field strength and the area of the conductor that is perpendicular to the magnetic field. In this case, the magnetic field strength is given as 1.5 Wb/m^2, the length of the conductor is 1m, and the angle between the velocity of the conductor and the direction of the magnetic field is 30 degrees. The area of the conductor that is perpendicular to the magnetic field can be calculated as the product of the length of the conductor and the component of its velocity that is perpendicular to the magnetic field. The component of velocity that is perpendicular to the magnetic field can be calculated as the product of the velocity and the sine of the angle between the velocity and the magnetic field direction. Thus, the e.m.f induced in the conductor can be calculated as follows: e.m.f = rate of change of magnetic flux = magnetic field strength * area of conductor perpendicular to magnetic field = 1.5 Wb/m^2 * (1m) * (50 m/s * sin(30 degrees)) = 37.5V Therefore, the e.m.f induced in the conductor is 37.5V.

Read lesson note on Force On A Current-Carrying Conductor In A Magnetic Field (JAMB)

Force On A Current-Carrying Conductor In A Magnetic Field

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Question 18 Report

Dispersion of white light is the ability of white light to

penetrate air, water and glass

move in a straight line

move around corners

separate to its component colours

Answer Details

White light is composed of a spectrum of colors that include red, orange, yellow, green, blue, indigo, and violet. These colors have different wavelengths and frequencies, which determine their position in the electromagnetic spectrum. When white light enters a medium like a prism, it slows down and bends, causing the different colors to refract at different angles. This process is called dispersion and results in the separation of white light into its component colors. The degree of refraction depends on the wavelength of the light, with shorter wavelengths refracting more than longer ones. As a result, the different colors of light are spread out, creating a spectrum of colors that is visible to the eye. Therefore, the answer to the question is: "Dispersion of white light is the ability of white light to separate into its component colors." In conclusion, the dispersion of white light is an important phenomenon in optics that allows us to see the different colors of the visible spectrum. It is caused by the different refractive indices of the colors of light, which leads to their separation when they pass through a medium like a prism.

Read lesson note on Electromagnetic Waves: Types Of Radiation In Electromagnetic Spectrum (WAEC)

Electromagnetic Waves: Types Of Radiation In Electromagnetic Spectrum

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Question 19 Report

A piece of radioactive material contains 1000 atmos. If its half -life is 20seconds, the time taken for 125 atoms to remain is

20 seconds

40 seconds

80 seconds

60 seconds

Answer Details

1000 → 500 → 250 → 125

20 + 20 + 20 = 60s

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Question 20 Report

The fuse in an electric device is always connected to the

neutral side of an electric supply

earth side of an electric supply

live side of an electric supply

terminal side of an electric supply

Answer Details

The fuse in an electric device is always connected to the live side of an electric supply. The live wire, also known as the "hot" wire, carries the electrical current from the power source to the device. The fuse is designed to protect the device and its components from damage in the event of an electrical surge or overloading. If the current becomes too high, the fuse will "blow," cutting off the flow of electricity and preventing the device from being damaged. By connecting the fuse to the live wire, it can protect the device from any electrical problems that may arise.

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Electrostatics

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Question 21 Report

The p-n junction diodes can act as rectifiers because they

conduct current when forward-biased

conduct current when reverse-biased

block current when forward-biased

conduct current in both directions

Electrostatics

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Question 22 Report

Two metals P and Q are heated through the same temperature difference. If the ratio of the linear expansivities of P to Q is 2:3 and the ratio of their
length is 3: 4 respectively, the ratio of the increase in lengths of P to Q is

1:2

2:1

8:9

9:8

Answer Details

The increase in length of a material due to heating is proportional to its linear expansivity and the change in temperature. The linear expansivity of a material is defined as the change in length per unit length per degree Celsius change in temperature. Let the increase in length of metal P be x, and the increase in length of metal Q be y. Let the temperature difference be ΔT. Then, we can write: x = αP ΔT Lp ...(1) y = αQ ΔT Lq ...(2) where αP and αQ are the linear expansivities of metals P and Q respectively, and Lp and Lq are their original lengths. We are given that the ratio of the linear expansivities of P to Q is 2:3. So, we can write: αP/αQ = 2/3 Cross-multiplying, we get: 3αP = 2αQ αP/αQ = 2/3 = 2k/3k ...(3) where k is a constant. We are also given that the ratio of the lengths of P to Q is 3:4. So, we can write: Lp/Lq = 3/4 Cross-multiplying, we get: 4Lp = 3Lq Lp/Lq = 3/4 = 3m/4m ...(4) where m is a constant. Substituting equations (3) and (4) into equations (1) and (2), we get: x = (2k/3k)αQ ΔT (3m) y = αQ ΔT (4m) Simplifying, we get: x/y = (2k/3k) (3/4) x/y = 1/2 Therefore, the ratio of the increase in lengths of P to Q is 1:2. Hence, the correct answer is 1:2.

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Thermal Expansion

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Question 23 Report

Clinical thermometers are examples of

pressure gas thermometer

resistance thermometer

alcohol thermometer

mercury- in - glass thermometer

Answer Details

Clinical thermometers are examples of mercury-in-glass thermometers. They consist of a thin, sealed glass tube that is filled with mercury. The glass tube has a narrow constriction in it, which prevents the mercury from flowing back down the tube once it has expanded due to a rise in temperature. When the thermometer is placed under the tongue or in the armpit, the heat from the body causes the mercury to expand and rise up the tube. The temperature can be read off a calibrated scale on the glass tube, which indicates the temperature based on the height of the mercury column. Mercury-in-glass thermometers are commonly used in clinical settings because they are accurate and have a fast response time. The mercury expands and contracts rapidly in response to temperature changes, allowing for quick and accurate temperature readings. Therefore, the correct answer is option (D) mercury-in-glass thermometer.

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Pressure

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Question 24 Report

After reflection from the concave mirror, rays of light from the sun converges

at the radius of curvature

at the focus

beyond the radius of curvature

between the focus and radius of curvature

Answer Details

A concave mirror is a spherical mirror with a reflecting surface that is curved inward. When parallel rays of light fall on a concave mirror, they are reflected in a way that depends on the distance between the mirror and the object, as well as the curvature of the mirror. If the object is located beyond the focal point of the concave mirror, the reflected rays will converge at a point between the focal point and the radius of curvature of the mirror. This point is known as a real image. However, if the object is located at a distance less than the focal length from the mirror, the reflected rays will diverge and not form a real image. Instead, they will form a virtual image that is located behind the mirror. In the case of the question, if rays of light from the sun fall on a concave mirror, and the mirror is positioned such that the sun's rays are parallel to its axis, then the reflected rays will converge at the focal point of the mirror. This is because the focal point is the point at which parallel rays of light, such as those from the sun, converge after reflection from the concave mirror. Therefore, the answer to the question is: "After reflection from the concave mirror, rays of light from the sun converge at the focus." In conclusion, the position of the object and the distance between the object and the concave mirror determine the nature of the image formed by the reflected rays of light. When the object is located at a distance greater than the focal length, a real image is formed that is inverted and smaller than the object. When the object is located at a distance less than the focal length, a virtual image is formed that is upright and larger than the object.

Read lesson note on Reflection Of Light At Plane And Curved Surfaces (JAMB)

Reflection Of Light At Plane And Curved Surfaces

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Question 25 Report

The magnification of an object 2cm tall when placed 10cm in front of a plane mirror is

6.0

1.0

0.7

0.6

Answer Details

When an object is placed in front of a plane mirror, its image appears to be behind the mirror, at the same distance from the mirror as the object is in front of it. The image appears to be a virtual image that is the same size as the object, but reversed from left to right. In this case, the object is 2cm tall and is placed 10cm in front of the mirror. The image will appear to be 10cm behind the mirror, which is the same distance as the object is in front of the mirror. The image will also be the same size as the object, which is 2cm tall. To find the magnification, we need to divide the height of the image by the height of the object: Magnification = height of image / height of object In this case, the height of the image is 2cm and the height of the object is also 2cm, so: Magnification = 2cm / 2cm = 1.0 Therefore, the magnification of the object when placed 10cm in front of a plane mirror is 1.0. This means that the image appears to be the same size as the object.

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Question 26 Report

If a reverse-biased voltage is applied across a p-n junction, the depletion layer width is

increased

decreased

constant

halved

Answer Details

A p-n junction is a boundary between a p-type semiconductor and an n-type semiconductor. When a reverse-biased voltage is applied across a p-n junction, the negative terminal of the voltage source is connected to the p-type semiconductor, and the positive terminal is connected to the n-type semiconductor. This creates an electric field that opposes the flow of current through the junction. The electric field pushes the majority carriers away from the junction, widening the depletion layer. The depletion layer is the region around the p-n junction where there are no free charge carriers. Therefore, the correct answer is that the depletion layer width is increased when a reverse-biased voltage is applied across a p-n junction.

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Electrostatics

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Question 27 Report

A block and tackle is used to raise a load of 250N through a vertical distance of 30m. What is the efficiency of the system if the work done against friction is 1500J?

62.5%

73.3%

83.3%

94.3%

Answer Details

A block and tackle is a system of pulleys that allows a person to lift a heavy load with less effort than it would take to lift the load directly. The efficiency of the block and tackle system is the ratio of the work output to the work input, expressed as a percentage. In this problem, the load being lifted is 250N, and it is being lifted through a vertical distance of 30m. The work done against friction is 1500J. We need to calculate the efficiency of the system. The work output of the system is the work done on the load, which is the product of the force applied to the load and the distance the load is lifted. In this case, the work output is: Work output = Force x Distance = 250N x 30m = 7500J The work input of the system is the work done by the person who is operating the block and tackle system. This includes the work done to lift the load as well as the work done against friction. We can calculate the work input as: Work input = Work output + Work against friction = 7500J + 1500J = 9000J Now we can calculate the efficiency of the system: Efficiency = (Work output / Work input) x 100% Efficiency = (7500J / 9000J) x 100% Efficiency = 83.3% Therefore, the efficiency of the system is 83.3%.

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Work, Energy And Power

Pressure

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Question 28 Report

I. Small size.
II. Low power requirement
III. Not easily damaged by high temperature
IV. Highly durable. Which of the above are the advantages of semiconductors?

I,II and lll only

ll,lll and lV only

l, Hand lV only

l, ll, lll and lV

Answer Details

Semiconductors are materials with electrical conductivity between conductors (like metals) and insulators (like ceramics). They are used extensively in electronic devices like transistors, diodes, and integrated circuits due to their unique properties, which include: I. Small size: Semiconductors can be fabricated into very small sizes, allowing for the production of compact electronic devices. II. Low power requirement: Semiconductors require very little power to operate, making them suitable for use in low-power devices like mobile phones and laptops. III. Not easily damaged by high temperature: Semiconductors can withstand high temperatures without damage, making them suitable for use in high-temperature applications like automotive and aerospace electronics. IV. Highly durable: Semiconductors are very durable and can withstand a lot of wear and tear, making them suitable for use in industrial and military applications. Therefore, the answer to the question is: "The advantages of semiconductors are I, II, III, and IV." In conclusion, semiconductors are a crucial component of modern electronics due to their unique properties. They allow for the production of small, low-power, and durable electronic devices that can withstand high temperatures, making them suitable for a wide range of applications.

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Structure Of The Atom (Nigeria Only)

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Question 29 Report

The pressure at any point in a liquid at rest depends only on the

depth and the density

mass and the volume

quantity and the surface area

surface area and the viscosity

Answer Details

The pressure at any point in a liquid at rest depends only on the depth and the density of the liquid. This is known as Pascal's principle or Pascal's law. According to this principle, the pressure at any point in a fluid is the same in all directions and is transmitted uniformly throughout the fluid. The pressure at a point in a liquid at rest is directly proportional to the depth of the point below the surface of the liquid. This is because the weight of the liquid above the point exerts a force on the liquid at the point, which results in a pressure that is directly proportional to the depth of the point. The pressure at a point in a liquid at rest is also directly proportional to the density of the liquid. This is because the weight of a given volume of liquid is proportional to its density, and the pressure at a point in the liquid is determined by the weight of the liquid above the point. Therefore, the pressure at any point in a liquid at rest depends only on the depth and the density of the liquid, and not on the mass, volume, quantity, surface area or viscosity of the liquid.

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Fluid At Rest

Pressure

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Question 30 Report

Calculate the total distance covered by a train before coming to rest if its initial speed is 30ms-1 with a constant retardation of 0.1m-2

5500m

4500m

4200m

3000m

Answer Details

To solve this problem, we can use the following kinematic equation: v^2 = u^2 + 2as where: - v is the final velocity (which is zero since the train comes to rest) - u is the initial velocity (which is 30 m/s) - a is the acceleration (which is the negative of the retardation, -0.1 m/s^2) - s is the distance covered Substituting the values into the equation, we get: 0^2 = (30 m/s)^2 + 2(-0.1 m/s^2)s Simplifying, we get: 0 = 900 - 0.2s 0.2s = 900 s = 4500 meters Therefore, the total distance covered by the train before coming to rest is 4500 meters. Explanation: When a train is moving with a certain velocity and then comes to rest due to a constant retardation, its total distance covered can be calculated using the above kinematic equation. This equation relates the initial velocity, final velocity, acceleration, and distance covered by the train. By substituting the given values into the equation and solving for the distance covered, we get the answer. In this case, the train starts with an initial velocity of 30 m/s and comes to rest with a constant retardation of 0.1 m/s^2. The total distance covered by the train before coming to rest is found to be 4500 meters.

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Motion

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Question 31 Report

The equation of a wave traveling in a horizontal direction is expressed as y = 15 sin 2/5 (60t - x) what is its wave length?

60m

15m

5m

2m

Production And Propagation Of Waves

Properties Of Waves: Reflection, Refraction, Diffraction

Types Of Waves

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Question 32 Report

In order to remove the error of parallax when talking measurements with a metre rule, the eye should be focused

slantingly towards the right on the markings

slantingly towards the left on the markings

vertically downwards on the markings

vertically upwards on the markings

Answer Details

When taking measurements with a meter rule, it is important to avoid parallax error. Parallax error occurs when the eye is not positioned correctly in relation to the meter rule markings, causing an incorrect reading to be taken. To avoid this error, the eye should be positioned directly above the marking being measured, looking vertically downwards at it. This ensures that the eye is perpendicular to the markings and there is no angle between the eye and the markings. Therefore, the correct answer is "vertically downwards on the markings." Focusing the eye slantingly towards the right or left on the markings, or vertically upwards, would introduce an angle between the eye and the markings, resulting in a parallax error.

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Measurements And Units

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Question 33 Report

A load is pulled at a uniform speed along a horizontal floor by a rope at 45 degree floor. If the force in the rope is 1500N, what is the frictional force on the load ?

1524N

1350N

1260N

1061N

Answer Details

F = mg cos 45 = 1500 x 0.708

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Read lesson note on Equilibrium Of Forces (WAEC)

Work, Energy And Power

Equilibrium Of Forces

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Question 34 Report

The quantity of heat energy required to melt completely 1 kg of ice at - 30oC is
[latent heat of fusion = 3.5 x 10 5Jkg -1, specific heat capacity of ice = 2.1x10 3Jkg -1K -1]

4.13x10 ⁶J

4.13x10 ⁵J

3.56x10 ⁴J

3.56x10 ²J

Answer Details

When a substance changes its phase, it either absorbs or releases heat energy. The amount of heat energy required to change the phase of a substance is known as the latent heat of fusion. In this case, we have to calculate the quantity of heat energy required to melt completely 1 kg of ice at -30°C. To do this, we need to use the following formula: Q = m Lf Where Q is the quantity of heat energy, m is the mass of the substance, and Lf is the latent heat of fusion. We are given that the mass of the ice is 1 kg, and the latent heat of fusion of ice is 3.5 x 10^5 Jkg^-1. So, substituting these values into the formula, we get: Q = 1 kg x 3.5 x 10^5 Jkg^-1 Q = 3.5 x 10^5 J This means that the quantity of heat energy required to melt completely 1 kg of ice at -30°C is 3.5 x 10^5 J. However, we need to be careful in calculating the quantity of heat energy required to lower the temperature of the ice from 0°C to -30°C before it starts melting. To do this, we need to use the following formula: Q = m c ΔT Where Q is the quantity of heat energy, m is the mass of the substance, c is the specific heat capacity of ice, and ΔT is the change in temperature. We are given that the mass of the ice is 1 kg, the specific heat capacity of ice is 2.1 x 10^3 Jkg^-1K^-1, and the change in temperature is 30°C. So, substituting these values into the formula, we get: Q = 1 kg x 2.1 x 10^3 Jkg^-1K^-1 x 30 K Q = 6.3 x 10^4 J Therefore, the total quantity of heat energy required to melt completely 1 kg of ice at -30°C is the sum of the quantity of heat energy required to lower the temperature of the ice from 0°C to -30°C and the quantity of heat energy required to melt the ice. Total Q = 6.3 x 10^4 J + 3.5 x 10^5 J Total Q = 4.13 x 10^5 J So, the correct answer is 4.13 x 10^5 J.

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Quantity Of Heat

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Question 35 Report

The process of detecting a pin mistakenly swallowed by a child is X-ray

Diagnosis

Therapy

Crystallography

Mammography

Answer Details

The process of detecting a pin mistakenly swallowed by a child is X-ray. X-ray is a diagnostic imaging tool that uses high-energy radiation to produce images of the internal structure of the body. In the case of a child swallowing a pin, an X-ray can be used to locate the position of the pin and determine if it is causing any harm. The X-ray produces a picture of the inside of the body, allowing medical professionals to see the location and position of the pin, and make any necessary medical decisions based on that information. So, X-ray is a diagnostic tool, not a therapy or a tool for crystallography or mammography.

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Structure Of The Atom (Nigeria Only)

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Question 36 Report

An object of volume 1 m 3 and mass 2kg is totally immersed in a liquid of density 1 kgm-3 . Calculate its apparent weight.

20N

10N

2N

1 N

Answer Details

The apparent weight of the object is the difference between the actual weight of the object and the buoyant force acting on it when it is immersed in a fluid. The buoyant force is equal to the weight of the fluid displaced by the object. In this case, the volume of the object is 1 m^3 and its mass is 2 kg, which means its density is 2 kg/m^3. The density of the liquid is given as 1 kg/m^3. Since the density of the object is greater than the density of the liquid, it will sink in the liquid. When the object is totally immersed in the liquid, it will displace a volume of liquid equal to its own volume. Therefore, the weight of the displaced liquid is given by the product of the volume and density of the liquid, which is 1 m^3 * 1 kg/m^3 = 1 kg. This is also the buoyant force acting on the object. The actual weight of the object is 2 kg * 9.81 m/s^2 = 19.62 N (where 9.81 m/s^2 is the acceleration due to gravity). Therefore, the apparent weight of the object is the difference between the actual weight and the buoyant force, which is 19.62 N - 1 kg * 9.81 m/s^2 = 9.81 N. Therefore, the apparent weight of the object is 9.81 N, which is closest to.

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Fluid At Rest

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Question 37 Report

A particle carrying a charge of 1. 0 x 10-8C enters a magnetic field at 3.0x 10-2 ms -1 at right angles to the field. If the force on this particle is 1.8 x 10-8N, what is the magnitude of the field?

6.0x10^-1T

6.0x10T

6.0x10^-3T

6.0x10^-4T

Answer Details

F = BQV

B =

\frac{F}{Q V}

B =

\frac{1.8 \times 10^{- 8}}{1.0 \times 10^{- 8} \times 3.0 \times 10^{- 2}}

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Electric Field

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Question 38 Report

Calculate the temperature change when 500J of heat is supplied to 100g of water

12.1⁰C

2.1^oC

1.2^oC

0.1^oC

Answer Details

To calculate the temperature change when a certain amount of heat is supplied to a substance, we can use the following formula: Q = m * c * ΔT where Q is the amount of heat supplied, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature. In this problem, we are given that 500J of heat is supplied to 100g of water. We know that the specific heat capacity of water is 4.18 J/(g·°C). So, we can substitute the values into the formula and solve for ΔT: Q = m * c * ΔT 500J = 100g * 4.18 J/(g·°C) * ΔT ΔT = 500J / (100g * 4.18 J/(g·°C)) ΔT = 1.2°C Therefore, the temperature change when 500J of heat is supplied to 100g of water is 1.2°C. In conclusion, the temperature change of a substance when heat is supplied to it depends on the specific heat capacity of the substance, the mass of the substance, and the amount of heat supplied. The formula for calculating the temperature change can be used to solve problems involving heat and temperature change.

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Temperature And Its Measurement

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Question 39 Report

If a load of 1 kg stretches a cord by 1.2cm, what is the force constant of the cord? {g=10ms-2}

866Nm-¹

833Nm-¹

769Nm-¹

667Nm-¹

Answer Details

The force constant of a cord represents the force required to stretch it by a unit length. In this case, the cord stretches by 1.2 cm when a load of 1 kg is applied to it. We can use Hooke's Law to find the force constant of the cord. Hooke's Law states that the force required to stretch a spring or cord is proportional to the amount of stretch. Mathematically, it can be expressed as F = kx, where F is the force, k is the force constant, and x is the amount of stretch. In this case, we know that the load applied is 1 kg or 1*10^3 g. We can convert this to mass in kg by dividing it by the acceleration due to gravity, g, which is given as 10 m/s^2. Therefore, the mass of the load is: m = 1*10^3 g / (10 m/s^2) = 100 g = 0.1 kg The amount of stretch, x, is given as 1.2 cm or 0.012 m. Using Hooke's Law, we can write: F = kx The force, F, required to stretch the cord by 0.012 m is equal to the weight of the load, which is: F = mg = 0.1 kg * 10 m/s^2 = 1 N Therefore, we can solve for the force constant, k, as: k = F/x = 1 N / 0.012 m = 83.3 N/m Thus, the force constant of the cord is 83.3 N/m. Looking at the answer options, we can see that option B is the closest to our answer of 83.3 N/m. Therefore, the correct answer is option B, 833 Nm^-1.

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Elasticity

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Question 40 Report

The characteristic of a vibration that determines its intensity is the

Frequency

Overtone

Wavelength

Amplitude

Answer Details

The characteristic of a vibration that determines its intensity, or how strong or weak it is, is the amplitude. The amplitude is the maximum displacement of a point on a vibrating body from its rest position. Simply put, it's the height of the vibration wave. The higher the amplitude, the stronger the vibration, and the more energy it carries. In contrast, a low amplitude vibration is weaker and carries less energy.

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Equilibrium Of Forces

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Question 41 Report

Which of the following particies CANNOT be deflected by both electric and magnetic fields?

Gamma rays

Alpha particles

Wave particles

Beta particles

Answer Details

Gamma rays cannot be deflected by both electric and magnetic fields. Gamma rays are high-energy electromagnetic radiation and do not have a charge, unlike alpha and beta particles. This means they are not affected by electric or magnetic fields and continue to travel in a straight line. On the other hand, alpha and beta particles, which are charged particles, can be deflected by electric and magnetic fields.

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Wave-particle Paradox

Electric Field

Electromagnetic Field (Part 2)

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Question 42 Report

I. It is a rapid, constant and irregular motion of tiny particles. II. It gives evidence that tiny particles of matter called molecules exist. III. It takes place only in gases. IV. It gives evidence that molecules are in a constant state of random motion. which of the combinations above is correct about Brownian notion?

I,II and III only

II,III and IV only

I,III and lV only

l, ll and lV only

Production And Propagation Of Waves

Properties Of Waves: Reflection, Refraction, Diffraction

Thermal Expansion

Structure Of Matter And Kinetic Theory

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