JAMB UTME - Physics - 2000
Question 1 Report
Dry
Day 1 - 30°C | Day 2 - 29°C | Day 3 - 25°CWet
Day 1 - 22°C | Day 2 - 22°C | Day 3 - 21°CThe reading above are for three consecutive days from a wet and dry bulb hygrometer. It can be concluded that the relative humidity for the three days
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Question 2 Report
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Question 3 Report
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∴ Heat lost by the metal = heat gained by the Calorimeter + Water
∴ 0.5 x C x [100 - 25]
80 x [25 - 15] + 420 [25 - 15]
0.5 x C x 75 = 80 x 10 + 420 x 10
37.5C = 800 + 4200
C = 5000/37.5 = 133.3Jkg-1K-1
Question 5 Report
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Question 6 Report
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4/3 = 6/app. depth
App Depth = (3 x 6)/4 = 4.5m
Question 7 Report
I. The frictional force is independent of the area of the surfaces in conduct
II. The frictional force depends on the nature of the surfaces in contact
III. The frictional force depends on the speed of sliding
IV. The frictional force is directly proportional to the normal reaction.Which combination of the above is true of sliding friction?
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Question 8 Report
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Question 9 Report
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Question 10 Report
The diagram above shows two capacitors P and Q of capacitance 5μF and 10μF. Find the charges stored in P and Q respectively
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∴ Qp = 5 x 10-b x 20
= 100 x 10-b or 100μC
Qp = 10 x 10-b x 70
= 200 x 10-b or 200μC
Correct option 100μC and 200μC
Question 11 Report
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Question 12 Report
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Question 13 Report
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Question 14 Report
I. Coherence
II. Same frequency
III. Same wavelength
IV. Same IntensityWhich of the conditions above are necessary to produce interference fringes?
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Question 15 Report
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√ 1/g
Since g, 2 and π are constant, => T ∝ √l
∴ T = K√l
Let the original length = l
thus for the length l, period T = 17s
∴ 17 = K√1 .................. [1]
Again, for the new length [1 - 1.5]
the period T = 8.5s
∴ 8.5 = k
√ [1-1.5] ...............[2]
thus dividing eqn [1] by eqn[2] we have
17/8.5 = √(l/l-1.5)
∴2 = √(l/l-1.5)
=>4 = (l/l-1.5)
∴l = 4[l-1.5]
= 4l - 6.0
∴4l - l = 6.0
3l = 6.0
l = 2.0m
Question 16 Report
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Question 17 Report
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Question 18 Report
If current flows in the direction of the arrows in the solenoid above, the north pole is at
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Question 19 Report
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Question 20 Report
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= 180 - 2i [since i = v]
∴ 120 = 180 - 2i
2i = 180 - 120
= 60
∴ i = 30o
Question 21 Report
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Question 22 Report
In the a.c circuit above, the current value is
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√ R2 x X2 =
√ 302 x 402
∴Z =
√ 2500 = 50W
But current I = V/Z = 200/50 = 4.00 A
Question 23 Report
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Question 24 Report
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Question 25 Report
The velocity y of a particle in a time t is given by the equation
Y = 10 + 2t2
Find the instantaneous acceleration after 5 seconds
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Question 26 Report
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U = Magnification = 24
But Magnification = V/U
∴ 24 = 72/U
U = 72/24
U = 3.0m
Question 27 Report
In the diagram above, the values of V1 and V2 are respectively
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Question 28 Report
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Question 29 Report
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Question 30 Report
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Question 31 Report
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Question 32 Report
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Question 33 Report
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Question 34 Report
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Question 35 Report
In a thermonuclear reaction, the total initial mass is 5.02 x 10-27kg and the total final mass is 0.01 x 10-27kg. The energy released in the process is
[c = 3.0 x 108ms-1]
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Energy = ∆mC2
∆m = Change in Mass
C = Speed of light
∴ 5.02 x 10-27 - 5.01 x 10-27 x [3 x 108]2
0.01 x 10-27 x 9 x 1016
E = 9.0 x 10-13J
Question 36 Report
The diagram above shows a maximum and minimum thermometer divided into three portions P, Q and R. Which of the following is true about the respective content of P,Q and R
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Question 37 Report
I. Its velocity is constant
II. No work is done on the body
III. It has constant acceleration directed away from the centre
IV. The centripetal force is directed towards the centreWhich combination of the above is true of a body moving with constant speed in a circular track?
Question 38 Report
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i.e. Work done = Q x V
But this work done is equal to the K.E. imparted to the charge given by K.E = 1/2MV2, where V is the velocity of the charge = Q x V = 1/2MV2
∴ p.d V = (1/2MV2)/Q
= 1/2 x 9.1-31 x [4 x 107]2/1.6 x 10-19
= 8 x 9.1 x 102/1.6
= 4550V
= 4.55 x 103V
Question 39 Report
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Question 40 Report
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75% = M.A/V.R
75/100 = M.A/5
M.A = 75(5)/100 = 3.75
But M.A = Load/Effort
3.75 = 150/Effort
Effort = 150/3.75
Effort = 40N
Question 41 Report
If the frequency of an emitted x-ray is 1.6 x 1016Hz, the accelerating potential is?
[e = 1.6 x 10-19C, h = 6.63 x 10-34Js]
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e x V = hf
∴ V = hf/e
(6.63 x 10-34 x 1.6 x 10-16)/1.6 x 10-19
= 6.63 x 10 = 66.3V
Question 42 Report
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Question 43 Report
A handbag containing some load weighing 162N is carried by two students each holding the handle of the bag next to him. If each handle is pulled \(60^\circ\) to the vertical, find the force on each student's arm
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Question 44 Report
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Voltage = 1.5KV = 1500V
Current (I) = P/V = 3000/1500 = 2Amps.
∴ Power loss in the cables = I2R
= 2 x 2 x 20
= 80W
Question 45 Report
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Question 46 Report
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eV = K.E.max, where V = stopping potential and K.E. = maximum kinetic energy of the photo emitted electron given by K.E. = Energy of incident rad - Work - function
= 5ev - 3ev = 2ev
∴ eV = 2eV
V = 2eV/e = 2V
∴ Stopping Potential = 2.0V
Question 47 Report
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0.75/V = adj/hyp = Cost30°
0.75/V = 0.8660
∴ V = 0.75/0.8660
V = 0.86-1
Question 48 Report
In the diagram above a beam of white light travels from a rare to a dense medium. What colours of light do the rays a, b and c respectively represents?
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Question 49 Report
