WAEC SSCE - Chemistry - 1993 (Objective)

Question 1 Report

When the trioxonitrate (IV) salt of an alkali metal Y is heated, the formula of the residue is

Y₂O

YNO₂

Y₂O₃

Y (NO₂)₂

YO₂

Chemical Combination

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Question 2 Report

Carbon is often deposited in the exhaust-pipe of cars because of the

presence of carbon in petrol

dehydrogenation of petrol

incomplete combustion of petrol

presence of additives in petrol

contamination of petrol with diesel

Answer Details

The carbon deposits in the exhaust pipe of cars are caused by the incomplete combustion of petrol. When petrol is burned, it reacts with oxygen to produce carbon dioxide and water vapor. However, if there is not enough oxygen, the petrol can only partially burn, leading to the formation of carbon particles (soot) that get carried through the exhaust system and eventually settle in the exhaust pipe. The presence of additives in petrol or contamination with diesel would not directly cause carbon deposits in the exhaust pipe.

Read lesson note on Chemistry Of Carbon Compounds (Nigeria Only) (WAEC)

Chemistry Of Carbon Compounds (Nigeria Only)

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Question 3 Report

Which of the following substances is a peroxide?

Na₂O₂

CuO

Pb_<3O₄

Fe₂O_<3

AI₂O_<3

Answer Details

The substance that is a peroxide is Na2O2. A peroxide is a compound that contains an oxygen-oxygen single bond, also known as a peroxide linkage. Na2O2 is a peroxide because it contains the peroxide linkage between the two oxygen atoms in the formula. In contrast, CuO, Pb3O4, Fe2O3, and AI2O3 do not contain a peroxide linkage and are not peroxides. In summary, Na2O2 is the only substance in the given options that is a peroxide because it contains an oxygen-oxygen single bond, which is a defining characteristic of peroxides.

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Acids, Bases And Salts

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Question 4 Report

Which of the following separation is routinely applied in the petroleum industry

Filtration

Chromatography

Evaporation

Fractional crystallization

Fractional distillation

Answer Details

The separation technique routinely applied in the petroleum industry is fractional distillation. Fractional distillation is a separation technique that separates a mixture of liquids into its individual components based on their boiling points. In the petroleum industry, crude oil, which is a mixture of various hydrocarbons, is heated and passed through a column that has several trays. Each tray has a different temperature, with the temperature increasing from the bottom to the top of the column. The hydrocarbons with lower boiling points vaporize and rise up the column, while those with higher boiling points remain as liquids and collect at the bottom. The vaporized hydrocarbons are then condensed and collected as fractions at different levels of the column. This process allows for the separation of crude oil into its individual components, such as gasoline, diesel, and kerosene.

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Solubility

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Question 5 Report

Examples of polymers include the following except

starch

nylon

wool

perspex

glass

Answer Details

Polymers are large molecules made up of repeating subunits called monomers. They can be natural or synthetic. Starch, nylon, wool, and perspex are examples of polymers because they are made up of repeating units of monomers. However, glass is not a polymer because it is not made up of repeating units of monomers. Instead, it is an amorphous solid that is made up of silicon dioxide (SiO2) molecules that are linked together in a random arrangement. Therefore, the correct answer is glass.

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Basic Biochemistry And Synthetic Polymers

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Question 6 Report

Some precious stones such as ruby and sapphire consist of aluminum oxide coloured by traces of the oxides of

group lV elements

group l metals

transition metals

alkaline earths

the halogens

Answer Details

Precious stones such as ruby and sapphire consist of aluminum oxide (Al₂O₃) colored by traces of transition metal oxides. The transition metal ions, such as chromium (Cr) and iron (Fe), replace some of the aluminum ions in the crystal lattice of the aluminum oxide, and give the stones their characteristic colors. For example, chromium gives rubies their red color and iron gives sapphires their blue color. Therefore, the correct option is "transition metals".

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Water

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Question 7 Report

Starch undergoes complete hydrolysis to produce

maltose

lactose

fructose

glucose

sucrose

Answer Details

Starch is a polysaccharide, which is a type of carbohydrate made up of many glucose units linked together. Complete hydrolysis of starch breaks down these glucose units into their monomers, resulting in the production of glucose. Therefore, the correct answer is glucose.

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Energy And Energy Changes

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Question 8 Report

Copper metal will react with concentrated trioxonitrate (V) acid to give?

Cu(NO₃)₃ + NO + N₂O₄ + H₂O

Cu(NO₃)₂ + NO + H₂O

CuO + NO₂ + H₂O

Cu(NO₂)₃ + NO₂ + H₂O

Water

Acids, Bases And Salts (Ghana Only)

Periodic Chemistry (Ghana Only)

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Question 9 Report

Producer gas is a mixture of

oxygen and hydrogen

Hydrogen and nitrogen

nitrogen and oxygen

nitrogen and carbon (ll) oxide

hydrogen and carbon (ll) oxide

Answer Details

Producer gas is a mixture of nitrogen and carbon (II) oxide. Producer gas is a fuel gas that is produced by heating a carbon-based fuel with a limited amount of oxygen or air. This process, called gasification, produces a mixture of gases that are collectively known as producer gas. The primary components of producer gas are nitrogen, which makes up the majority of the gas, and carbon (II) oxide, which is the second most abundant component. Other minor components may include hydrogen, methane, and other gases, depending on the type of fuel and the gasification process used. So, in summary, producer gas is mainly made up of nitrogen and carbon (II) oxide, with some minor amounts of other gases.

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Read lesson note on Separation Of Mixtures And Purification Of Chemical Substances (JAMB)

Kinetic Theory Of Matter And Gas Laws

Separation Of Mixtures And Purification Of Chemical Substances

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Question 10 Report

When ammonium chloride is dissolved in water in a test tube, the tube feels colder showing that

the solution is unsaturated

sublimation has ocurred

ammonia gas is evolved

the process is endothermic

condensation has occurred

Answer Details

The process is endothermic when ammonium chloride is dissolved in water in a test tube. When ammonium chloride is dissolved in water, it absorbs heat from the surroundings to break apart the ionic bonds between the ammonium and chloride ions. This means that the process requires energy to take place and absorbs heat from the surrounding environment. As a result, the test tube containing the solution feels colder to the touch, indicating that heat is being transferred from the surroundings to the solution. In summary, the cooling effect observed when ammonium chloride is dissolved in water in a test tube is due to the endothermic process of breaking apart ionic bonds, which absorbs heat from the surroundings.

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Oxidation And Reduction

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Question 11 Report

Which of the following is correct about the electrons in the 1s orbital? They

have the same spin

are easier to remove than those in the 2p orbital

are closest to the nucleus

have the same energy as those in the 2s orbital

have different magnetic quantum numbers

Answer Details

The correct option about the electrons in the 1s orbital is that they are closest to the nucleus. The 1s orbital is the lowest energy level in an atom, and it is located closest to the nucleus, which has a positive charge. The closer an electron is to the nucleus, the stronger the attractive force between them, so electrons in the 1s orbital are more strongly attracted to the nucleus than those in other orbitals. This makes them harder to remove from the atom, and they require more energy to be ionized. The other options are not correct: electrons in the 1s orbital do not necessarily have the same spin, they are not easier to remove than those in the 2p orbital, they do not have the same energy as those in the 2s orbital, and they do not have different magnetic quantum numbers.

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Question 12 Report

Alkanes are used mainly

in the production of plastics

as domestic and industrial fuels

in the textile industry

in the hydrogenation of oils

as fine chemicals

Answer Details

Alkanes are primarily used as domestic and industrial fuels. Alkanes are a group of hydrocarbons that contain only single bonds between carbon atoms and are therefore relatively inert. They are obtained from crude oil and natural gas and can be used as fuels for heating and cooking in households and industries. In addition to their use as fuels, alkanes are also used in the production of plastics, where they serve as starting materials for the synthesis of various types of plastics. They are also used in the hydrogenation of oils to produce margarine, and as fine chemicals, where they are used as solvents, lubricants, and as a starting material in the synthesis of pharmaceuticals and other specialty chemicals. However, these applications are not as significant as their use as fuels.

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Read lesson note on Periodic Chemistry (Ghana Only) (WAEC)

Chemistry, Industry And The Environment

Periodic Chemistry (Ghana Only)

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Question 13 Report

Sulphur burns in air to form

an acidic oxide

a basic oxide

an amphoteric oxide

a neutra oxide

a mixed oxide

Answer Details

Sulphur burns in air to form an acidic oxide, which is sulfur dioxide (SO2). When sulfur burns in air, it reacts with oxygen to form sulfur dioxide gas. Sulfur dioxide is an acidic oxide because it reacts with water in the air to form sulfurous acid, which has a pH lower than 7. This means that it can react with bases to form salts and water. Sulfur dioxide is also a major air pollutant that can cause respiratory problems and acid rain when it dissolves in rainwater. In summary, when sulfur burns in air, it forms sulfur dioxide, which is an acidic oxide that can react with water to form sulfurous acid and can contribute to air pollution and acid rain.

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Read lesson note on Acids, Bases And Salts (JAMB)

Metals And Their Compounds

Acids, Bases And Salts

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Question 14 Report

Which of the following indicates the correct increasing order of oxidizing power of the halogens?

F < CI < Br < l

l < Br < CI < F

I < CI < Br < F

Br < I < CI < F

CI < F < I < Br

Answer Details

The oxidizing power of a halogen is related to its ability to gain electrons. Halogens have seven electrons in their outermost shell and require one more electron to complete their octet configuration. The process of gaining an electron involves reduction of the halogen. The halogens are arranged in the periodic table in order of increasing atomic number, so the trend in oxidizing power can be related to this arrangement. As we move down the group, the atomic radius of the halogens increases, and the valence electrons become farther away from the nucleus, which means it becomes harder to attract electrons and so the oxidizing power decreases. Therefore, the correct increasing order of oxidizing power of the halogens is: I < Br < Cl < F. Hence, is correct.

Read lesson note on Oxidation And Reduction (JAMB)

Oxidation And Reduction

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Question 15 Report

Which of the following solids has a network structure?

Diamond

lodine

Sulphur

Graphite

lron

Answer Details

Diamond has a network structure. In a network structure, all the atoms in the solid are covalently bonded to each other forming a giant molecule. In diamond, each carbon atom is covalently bonded to four other carbon atoms forming a tetrahedral structure, creating a three-dimensional network of carbon atoms bonded together. This network structure is responsible for diamond's unique physical and chemical properties such as high hardness and thermal conductivity.

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Read lesson note on Periodic Chemistry (Ghana Only) (WAEC)

Atomic Structure And Bonding

Periodic Chemistry (Ghana Only)

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Question 16 Report

Which of the following pieces of deposited if a current of 10A was passed through a solution of copper(ll) salt for 965 seconds? (1F = 96500 C)

0.005 mole

0.025 mole

0.05 mole

1.00 mole

1.05 mole

Electrolysis

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Question 17 Report

Trioxosulphate (lV) acid is not stored for a long period because it

is a weak dibasic acid

has bleaching properties

is unstable and eaily decomposed

smells strongly of sulphur (lV) oxide

can act as a germicide

Answer Details

Trioxosulphate (lV) acid, also known as sulfuric acid, is not stored for a long period because it is an unstable and easily decomposed compound. This means that over time, it breaks down into other substances, making it less effective for its intended use. Additionally, the decomposition of sulfuric acid can lead to the formation of hazardous byproducts, which can be dangerous if not properly handled. Therefore, it is essential to use and store sulfuric acid with caution and care.

Read lesson note on Acids, Bases And Salts (Ghana Only) (WAEC)

Acids, Bases And Salts (Ghana Only)

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Question 18 Report

In which of the following pairs are both substances deliquescent?

CaCI₂ and H₂SO₄

NaOH and MgSO₄ 7H₂O

CaCI₂ and NaOH

CUO and NaCI

CaCO₃ and MgCI₂

SOLUBILITY OF SUBSTANCES (Nigeria Only)

Acids, Bases And Salts (Ghana Only)

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Question 19 Report

An alkene may be converted to an alkane by

halogenation

hydrolysis

dehydration

hydrogenation

decomposition

Answer Details

An alkene is a hydrocarbon that contains a carbon-carbon double bond, whereas an alkane is a hydrocarbon that contains only single bonds between the carbon atoms. The process that converts an alkene to an alkane is called hydrogenation, which involves the addition of hydrogen gas (H2) across the carbon-carbon double bond. In this reaction, the double bond is broken, and the two carbon atoms are each bonded to a hydrogen atom, forming a single bond. This reaction is commonly carried out in the presence of a metal catalyst, such as platinum, palladium, or nickel, which speeds up the reaction by facilitating the adsorption of hydrogen molecules onto the surface of the metal. Therefore, the correct answer is hydrogenation.

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Chemical Bonds (Nigeria Only)

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Question 20 Report

The alloy used for metal work and plumbing contains

lead and tin

iron and carbon

copper and tin

aluminium and copper

lead and antimony

Metals And Their Compounds

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Question 21 Report

Which of the following compounds of tin is a strong reducing agent?

SnCI₂

SnCI₄

SnO₂

SnH₄

Sn(OH)₂

Answer Details

The compound SnH₄ (tin(IV) hydride) is a strong reducing agent. This is because it can easily donate its hydrogen atoms, which act as reducing agents. In other words, SnH₄ can easily give up electrons to other compounds, causing them to be reduced. This property of SnH₄ makes it useful in a variety of chemical reactions, particularly in organic chemistry. On the other hand, SnCl₂, SnCl₄, SnO₂, and Sn(OH)₂ are not strong reducing agents. SnCl₂ and SnCl₄ are both tin(IV) compounds and do not contain any hydrogen atoms that can act as reducing agents. SnO₂ and Sn(OH)₂ contain oxygen and hydroxide groups respectively, which do not have a tendency to give up electrons and are not strong reducing agents.

Read lesson note on Oxidation And Reduction (JAMB)

Oxidation And Reduction

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Question 22 Report

Which of the following pairs illustrates isotopy?

But-l-ene and but -2-ene

Ortho-hydrogen and parahydrogen

Oxygen and ozone

Hydrogen and deuterium

Alpha-particle and beta-particle

Answer Details

The pair that illustrates isotopy is hydrogen and deuterium. Isotopy refers to the phenomenon where two atoms of different elements have the same atomic number but different atomic masses due to a different number of neutrons in their nuclei. Hydrogen and deuterium are both elements with atomic number 1, but deuterium has one neutron in its nucleus in addition to the proton, while hydrogen has no neutron. Therefore, they are isotopes of each other. In contrast, the other options are not examples of isotopy. But-l-ene and but-2-ene are structural isomers, ortho-hydrogen and para-hydrogen are different spin isomers, oxygen and ozone are allotropes of the same element, and alpha and beta particles are different types of subatomic particles.

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Structure Of The Atom

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Question 23 Report

In which of the following changes is ∆S negative ?

H₂O_(l) → H₂O_(s)

C_(s) + 1/2O_{2,/sub>_(g) → CO_(g)}

PCI₅_(g) → PCl₃_(g) + Cl₂_(g)

NaCl_(s) + aq →Na₊ _(aq) + Cl_- _(aq)

NH₃_(g) + HCl_(g)

Answer Details

The change in entropy (∆S) is a measure of the disorder or randomness of a system. A negative ∆S indicates that there is a decrease in disorder or randomness. In the given options: - The first option is a phase change from liquid to solid, which is typically associated with a decrease in entropy. So, ∆S is negative. - The second option involves the formation of a gas, which is typically associated with an increase in entropy. So, ∆S is positive. - The third option involves the decomposition of a solid into gases, which is typically associated with an increase in entropy. So, ∆S is positive. - The fourth option is the dissociation of a salt into its ions, which is typically associated with an increase in entropy. So, ∆S is positive. - The fifth option involves the formation of a gas, which is typically associated with an increase in entropy. So, ∆S is positive. Therefore, the only change in which ∆S is negative is H₂O_(l) → H₂O_(s).

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Chemical Kinetics And Equilibrium Systems (Ghana Only)

Chemical Industry And Environment

States Of Matter

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Question 24 Report

What does X atand for in the following expression? X = Log₍₁₀₎(H⁺)

Enthalpy change (∆H)

Equilibrium constant (K)

Solubility product

Degree of acidity (pH)

lonic product of water

Answer Details

In the expression X = Log₍₁₀₎(H⁺), the variable X stands for the degree of acidity, commonly known as pH. The pH of a solution is a measure of its hydrogen ion concentration. The logarithmic function in this expression relates the hydrogen ion concentration to the pH scale, which ranges from 0 to 14. A pH of 7 is considered neutral, while values below 7 are acidic and values above 7 are basic. The pH scale is widely used in chemistry and biology to describe the acidity or basicity of a solution, and it is an important parameter in many chemical reactions and biological processes.

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Solubility Of Substances (Ghana Only)

Acids, Bases And Salts (Ghana Only)

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Question 25 Report

The component of air that removed when air is bubbled into alkaline pyrogallol solution is

carbon(lV) oxide

oxgyen

water vapour

nitrogen

helium

Answer Details

The component of air that is removed when air is bubbled into alkaline pyrogallol solution is oxygen. Alkaline pyrogallol solution is a reagent that is used to absorb oxygen from a gas mixture. When air is bubbled into this solution, the oxygen present in the air reacts with pyrogallol and gets absorbed, forming a brown precipitate of the oxidized pyrogallol. The other components of air, such as nitrogen, carbon dioxide, water vapor, and other gases, remain unchanged and do not react with pyrogallol. Therefore, the correct answer is: - Oxygen

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Read lesson note on Oxidation And Reduction (JAMB)

Air

Oxidation And Reduction

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Question 26 Report

Chlorine is is used in water treatment as

a germicide

a decolorizing agent

an antioxidant

a coagulating agent

an aerating agent

Answer Details

Chlorine is used in water treatment as a germicide. Water treatment is a process of purifying water to make it safe for human consumption. One of the most common methods of water treatment involves the use of chlorine. Chlorine is added to water to kill harmful microorganisms such as bacteria and viruses that can cause waterborne diseases like cholera, typhoid fever, and dysentery. Chlorine works by disrupting the cellular function of microorganisms and breaking down their cell walls. This makes them unable to reproduce and eventually causes them to die off. Chlorine is effective against a wide range of microorganisms and is relatively inexpensive compared to other water treatment methods. In summary, chlorine is used in water treatment as a germicide because it is effective at killing harmful microorganisms in water and making it safe for human consumption.

Read lesson note on Acids, Bases And Salts (Ghana Only) (WAEC)

Acids, Bases And Salts (Ghana Only)

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Question 27 Report

Which of the following will not affect the degree of hardness in a sample of temporarily hard water?

Addition of washing soda

Adding of soap

Treatment with carbon exchange resin

Filtration

Distillation

Solubility Of Substances (Ghana Only)

Acids, Bases And Salts (Ghana Only)

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Question 28 Report

Which of the following gases are diatomic except

nitrogen

helium

hydrogen

fluorine

oxygen

Answer Details

A diatomic molecule is a molecule composed of two atoms, whether they are of the same element or not. Therefore, the gases that are diatomic have molecules that consist of two atoms. Nitrogen, hydrogen, fluorine, and oxygen are diatomic gases, which means they exist as molecules composed of two atoms of the same element. On the other hand, helium is a monatomic gas, meaning it exists as individual atoms and not as molecules consisting of multiple atoms. Therefore, helium is the gas among the options given that is not diatomic.

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Kinetic Theory Of Matter And Gas Laws

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Question 29 Report

Consider the reaction represented by the following equation CaCI₂ _(aq) + H ₂C₂O ₄_(aq) ⇌ CaC ₂O₄_(s) + 2HCI_(aq). Which of the following would dissolve the precipitate of CaC ₂O₄ formed?

Stirring the mixture vigorously

Adding more calcium chloride solution

lncreasing the concentration of the ethanedioic acid

Adding concentrated hydrochloric acid

Adding some distilled water

Answer Details

The formation of a precipitate in this reaction indicates that CaC ₂O₄ is insoluble in water. In order to dissolve the precipitate, we need to find a substance that can react with it to form a soluble compound. , adding concentrated hydrochloric acid, is the correct answer. This is because the reaction between CaC ₂O₄ and HCl produces soluble calcium chloride (CaCl ₂) and carbon dioxide (CO ₂). The balanced chemical equation for this reaction is: CaC ₂O₄ + 4HCl → CaCl ₂ + 2CO ₂ + 2H ₂O The carbon dioxide gas will escape as bubbles, leaving behind a solution of CaCl ₂, which is soluble in water. The other options will not dissolve the CaC ₂O₄ precipitate. Stirring the mixture vigorously will not change the chemical nature of the substances in the solution. Adding more calcium chloride solution will not react with the CaC ₂O₄ precipitate since it is already present in excess. Increasing the concentration of ethanedioic acid will not react with CaC ₂O₄ either, as it is a weak acid and cannot displace the strong acid HCl. Adding distilled water will not dissolve the precipitate since CaC ₂O₄ is insoluble in water.

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Acids, Bases And Salts

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Question 30 Report

The following gases decolorize bromine water except

C₂H₆

C₂H₄

C₂H₂

C₃H₄

C₃H₆

Answer Details

Bromine water is a reddish-brown solution of bromine in water. When an unsaturated hydrocarbon gas (C₂H₄, C₂H₂, C₃H₄, C₃H₆) is passed through the bromine water, the double or triple bond of the hydrocarbon is broken, and the bromine is added across the double or triple bond. This results in the decolorization of the bromine water. On the other hand, when a saturated hydrocarbon gas such as ethane (C₂H₆) is passed through bromine water, there is no double or triple bond to break, and therefore no bromine is added to the molecule. Thus, bromine water is not decolorized by ethane. Therefore, the correct answer to the question is C₂H₆.

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Kinetic Theory Of Matter And Gas Laws

Separation Of Mixtures And Purification Of Chemical Substances

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Question 31 Report

The product of the reaction between ethanol and excess acidified K_{2_{Cr₂O₂ is}}

ethanal

ethylethanoate

ethanoic acid

ethyne

ethanedioic acid

Answer Details

The product of the reaction between ethanol and excess acidified K_{2_{Cr₂O₂ is ethanoic acid. The reaction is an oxidation reaction where ethanol is oxidized to ethanoic acid and K_{2_{Cr₂O₂ is reduced to Cr³⁺. The acidified K_{2_{Cr₂O₂ acts as an oxidizing agent and removes hydrogen from the ethanol molecule, producing ethanoic acid. Therefore, the correct answer is ethanoic acid.}}}}}}

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Acids, Bases And Salts

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Question 32 Report

What volume of distilled water should be added to 400cm3 of 2.0 mole dm-3 \(H_{2}SO_{4}\) to obtain 0.20 mole dm-3 of solution>

600cm-³

800cm-³

1,000cm-³

3,600cm-³

4,000cm-³

Answer Details

This is a dilution problem in chemistry. The formula for dilution is C₁V₁ = C₂V₂, where C₁ and V₁ are the initial concentration and volume, respectively, and C₂ and V₂ are the final concentration and volume, respectively. We can rearrange the formula to solve for V₂: V₂ = (C₁V₁)/C₂ Substituting the values given in the question, we get: V₂ = (2.0 mol dm^-3 x 400 cm³)/0.20 mol dm^-3 Simplifying the expression, we get: V₂ = 4,000 cm³ Therefore, 4,000cm³ of solution is needed. However, the question is asking for the volume of distilled water to add, so we need to subtract the initial volume from the final volume to get the volume of distilled water needed: Volume of distilled water = V₂ - V₁ = 4,000 cm³ - 400 cm³ = 3,600 cm³ Hence, the correct option is 3,600 cm³.

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Kinetic Theory Of Matter And Gas Laws

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Question 33 Report

Zinc displaces copper from an aqueous solution of copper (ll) salt because

copper is a transition element

copper is a moderately reactive metal

Zinc and copper have reducing prperties

zinc is more reactive than copper

zinc reacts with both acids and alkalis

Answer Details

Zinc displaces copper from an aqueous solution of copper (II) salt because zinc is more reactive than copper. Reactivity is the tendency of a metal to lose electrons and form positive ions. Metals that have a higher tendency to lose electrons are more reactive than those with a lower tendency. Zinc is more reactive than copper, which means it has a greater tendency to lose electrons and form positive ions. When zinc is added to an aqueous solution of copper (II) salt, such as copper (II) sulfate, the zinc atoms lose electrons to form zinc ions. These zinc ions then react with the copper ions in the solution by displacing them from the copper (II) sulfate. The displaced copper ions then form a solid layer of copper on the surface of the zinc metal, which can be observed as a red-brown coating on the zinc. Therefore, the reason why zinc displaces copper from an aqueous solution of copper (II) salt is that zinc is more reactive than copper, and it has a greater tendency to lose electrons and form positive ions.

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Kinetic Theory Of Matter And Gas Laws

Metals And Their Compounds

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